Answer:
I think the answer would be D
D = EE x Ee
Explanation:
Not all do so your answer is false
Factors such as age, gender, family history, and genetics are <u>nonmodifiable</u><u /> risk factors, while <u>modifiable</u><u /> risk factors are ones that are in your power to change.
You cannot change your age, family history or genetics - you will age no matter what, and you will inherit some traits from your ancestors whether you like it or not. Gender is more flexible nowadays as there are surgeries that can help people change their gender.
Q = recessive allele frequency = 0.3, and thus in H-W equilibrium there are ONLY two alleles, q (recessive) and
p (dominant). Therefore all of the p and q present for this gene in a population must account for 100% of this gene's alleles. And 100% = 1.00.
So p, the dominant allele frequency, must be equal to 1 - q --> p = 1 - q
p = 1 - 0.3 = 0.7.
Since heterozygotes are a combination of the p and q, we must again look at the frequencies of each genotype: p + q = 1, then (p+q)^2 = 1^2
So multiplying out (p+q)(p+q) = 1, we get: p^2+2pq+q^2 = 1 (all genotypes), where p^2 = frequency of homozygous dominant individuals, 2pq = frequency of heterozygous individuals, and q^2 = frequency of homozygous recessive individuals.
Therefore if the population is in H-W equilibrium, then the expected frequency of heterozygous individuals = 2pq = 2(0.7)(0.3)
2pq = 2(0.21) = 0.42, or 42% of the population.
Hope that helps you to understand how to solve population genetics problems!
Answer:
B Requires building dams that can harm ecosystems
