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irina [24]
3 years ago
13

One number is 6 less than a second number. twice the second number is 9 less than 5 times the first. find the two numbers

Mathematics
1 answer:
Ymorist [56]3 years ago
7 0
Ssssssssssssssssssssssssssssssssss
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-9=6+x zzzzZZZzzzzzzzzz
horrorfan [7]

Answer:

-15

Step-by-step explanation:

Isolate x to solve

-9=6+x

-6  -6

-15=x

4 0
3 years ago
Read 2 more answers
Identify 3 major arcs of circle that contain point A?
natita [175]

Answer:

Minor Arcs (two capital letters) Arcs that have a degree measure of less than 180 degrees.

Major Arc (three capital letters) Arcs that have a degree measure greater than 180 degrees.

Semi Circle (three capital letters) Arcs that have a degree measure equal to 180 degrees.Step-by-step explanation:

3 0
2 years ago
Simplify: (−2a2b) • (4a5b2)<br> please can someone help!
xz_007 [3.2K]
Hey there hope this helps you out

5 0
3 years ago
If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No
Effectus [21]

If A and B are independent, then P(A\cap B)=P(A)P(B).

a.

P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)

P(A\cup B)=0.5+0.2-0.5\cdot0.2

\boxed{P(A\cup B)=0.6}

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)

P(A^c\cap B^c)=1-0.6

\boxed{P(A^c\cap B^c)=0.4}

c. DeMorgan's law can be used here too:

P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)

P(A^c\cup B^c)=1-0.5\cdot0.2

\boxed{P(A^c\cup B^c)=0.9}

4 0
3 years ago
If theta is an acute angle and sin=1/2 , then cos theta =
lilavasa [31]
\pi /6 is the only acute angle whose sin = 1/2. Therefore, cos (\pi /6) = \sqrt{3} /2
7 0
3 years ago
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