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2 years ago

Write the equation of the line perpendicular to y =5/6x+1/6 that passes through the point (-9,3)

Mathematics

1 answer:

tiny-mole [99]2 years ago

7 0

Answer:

y = -6/5x + 13 4/5

Step-by-step explanation:

Step 1: Perpendicular slope

We need to find the perpendicular slope, or the opposite reciprocal.

This means we change the sign (positive, negative)and flip the numbers

Perpendicular sope to 5/6x = -5/6x = -6/5x

Step 2: Plug in coordinates

Now we plug in the coordinates for y = -6/5x + b

3 = -6/5(9) + b

3 = -10.8 + b

b = 13.8 or 13 4/5

-Chetan K

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$\displaystyle\iint_\sigma\mathbf F\cdot\mathrm dS$
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$\mathbf r_u=\dfrac\partial{\partial u}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=\mathbf k$
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$\mathbf r_u\times\mathbf r_v=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&1\\-2\sin v&\cos v&0\end{vmatrix}=-\cos v\,\mathbf i-2\sin v\,\mathbf j$

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$\displaystyle5\int_0^0e^t\,\mathrm dt+5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv$

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