4 years ago

8' 10" − 4' 11" I need help

Mathematics

1 answer:

Masja [62]4 years ago

4 0

Answer:

3' 11"

Step-by-step explanation:

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Solve for x. A. 6/3 B. 5 C. 12 D. 12.5

belka [17]

Answer:

x=12

Step-by-step explanation:

Using Proportion:

$\tt \cfrac{x}{16} =\cfrac{9}{x}$

$\tt x^2=9(16)$

$\tt x=12$

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2 years ago

9. Lillie's grandmother is making dinner

Andreyy89

The answer would be 8

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3 years ago

The sum of two numbers is 186.The difference between the same numbers is 32. What are the two numbers?

ad-work [718]

182 divided by 2 is 93.Then you subtract 32 from 93 and get 61.SO they two numbers you are looking for is 93 and 61

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4 years ago

(cos x - (sqrt 2)/2)(sec x -1)=0

Darya [45]

$(\cos x-\frac{\sqrt{2}}{2})(\sec x-1)$ =0 [/tex]

$=(\cos x-\frac{1}{\sqrt{2}})(\sec x-1)$ =0 [/tex]

$\frac{(\sqrt{2}\cos x-1)}{\sqrt{2}}(\frac{1}{\cos x\ }-1)=0$

(Reciprocal Identity)

$(\frac{^{\sqrt{2}\\cos x-1}}{^{\sqrt{2}}})(\frac{1-\cos x}{\cos x})=0$

$\frac{^{(\sqrt{2}\cos x-1})}{\sqrt{2}}\frac{(1-\cos x)}{\cos x}=0$

$(\sqrt{2}\cos x-1}){(1-\cos x)}=0$ (ZeroProduct Property)

$\sqrt{2}\cos x-1=0$

$\sqrt{2}\cos x=1$

$\cos x=\frac{1}{\sqrt{2}}$

$x=\frac{\Pi }{4}$

and

$1-\cos x=0$

$\cos x=1$

$x=0$

x=0 and x= $\frac{\Pi }{4}$ are the solutions.

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4 years ago

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Susan is attending a talk at her son's school. There are 8 rows of 10 chairs where 54 parents are sitting.

Vesnalui [34]

Answer:

The answer is 3.

Hope it helped!

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3 years ago

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