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Anvisha [2.4K]
3 years ago
14

Multiply (1/6)(-1/2)

Mathematics
2 answers:
Vesnalui [34]3 years ago
8 0

Answer:

the answer is -1/12

lidiya [134]3 years ago
7 0

Answer:

b is your answer

Step-by-step explanation:

This is because 1/6 divided by -1/2 = -1/12

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This one is the one I need help with my final question
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vertex C could be at (6,0) or (2,8)

(I'm sorry if I'm wrong, but if not I hope this helps!)

Step-by-step explanation:

vertex C needs to be placed somewhere on the graph where it would form a right angle (and therefore a right-angled triangle as well). vertex C could be at (6,0) or (2,8). this is because at these two points vertex C will form a right angle, therefore making it a right-angled triangle.

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Circle T is shown. Angle Q S R intercepts arc Q R. Angle Q S R is 52 degrees. What is the measure of arc Q R? 26° 52° 104° 128°
victus00 [196]

Answer:

104 degrees'

Step-by-step explanation:

Find the diagram attached

According to the theorem;

Angle at the vertex is half the angle at its intercepted arc

Given

Angle at the vertex = 52 degrees

Angle at the intercepted arc = arc QR

Hence;

52 = 1/2 arcQR

Cross multiply

52 * 2 = arcQR

104 = arc QR

Swap

arc QR = 104 degrees'

5 0
2 years ago
Read 2 more answers
1. Find the area of the region bounded above by y = e^x, bounded below by y = x, and bounded on the sides
salantis [7]

The area of the region bounded above by y= eˣ bounded by y = x, and bounded on the sides; x =0; and x = 1 is given as e¹ - 1.5.

<h3>What is the significance of "Area under the curve"?</h3>

This is the condition in which one process increases a quantity at a certain rate and another process decreases the same quantity at the same rate, and the "area" (actually the integral of the difference between those two rates integrated over a given period of time) is the accumulated effect of those two processes.

<h3>What is the justification for the above answer?</h3>

Area = \int\limits^1_0 {(e^x-x)} \, dx

= \int\limits^1_0 {e^x-x} \, dx - \int\limits^1_0 {(x)} \, dx

= e¹-(1/2-0); or

Area = e -1.5 Squared Unit

The related Graph is attached accordingly.

Learn more about area bounded by curve:
brainly.com/question/27866606
#SPJ1

3 0
1 year ago
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