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tatyana61 [14]
3 years ago
11

The length of a rectangle is 1 more than 3 times the width. 5 times the length is 45 more than the perimeter. Find the dimension

s.
Mathematics
1 answer:
Murljashka [212]3 years ago
3 0

Answer:

width = w

length= 3w+1

perimeter= 5(3w+1) -45

perimeter     =   2(l+b)

5(3w+1) -45 = 2{(3w+1)+w}

  15w  - 40   =  8w+2

             6w  = 42

               w  =7

therefore width = <u>7</u>

 length= 3w+1  =  <u>22</u>

perimeter=  <u>65</u>

Step-by-step explanation:

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In a competition, a school awarded medals in different categiories.40 medals in sport 25 medals in danceand 212 medals in music,
aleksley [76]

Answer:

210

Step-by-step explanation:

Given:

Medals in sports = 40

Medals in dance = 25

Medals in music = 212

Total students that received medals = 55

Total students that received medals in all three categories = 6

Required:

How many students get medals in exactly two of these categories?

Take the following:

A = set of persons who got medals in sports.

B = set of persons who got medals in dance

C = set of persons who got medals in music.

Therefore,

n(A) = 40

n(B) = 25

n(C) = 212

n(A∪B∪C)= 55

n(A∩B∩C)= 6

To find how many students get medals in exactly two of these categories, we have:

n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)

=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)

n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)

Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)

Using equation 1:

=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18

Substitute values in the equation:

= 40 + 25 + 212 + 6 − 55 − 18

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6 0
4 years ago
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Answer:

(-10,-10)

Step-by-step explanation:

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I will rewrite the system with that manipulation:

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9x     =-90 where I subtracted 90 on both sides.

x=       -10 where I divided both sides by 9.

The solution is (x,y)=(-10,-10)

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