I started cooking at4:55 PM I finish cooking at 6:18 PM how long did I cook

2 answers:

8 0

You need to subtract times.
If you need to borrow an hour, borrow and hour, and add 60 minutes to the minute part. Then subtract.

6:18 pm - 4:55 pm

Borrow 1 hour from the 6 hours leaving 5 hours.
The borrowed hour is 60 minutes.
Add the 60 minutes to the 18 minutes making 78 minutes.
Now you are subtracting 4:55 from 5:78.
Subtract 4 from 5 to give you hours.
Subtract 55 from 78 to give you minutes.

6:18 5:78
- 4:55 - 4:55
---------- ---------
1:23

Answer: You cooked for 1 hour and 23 minutes.

Mars2501 [29]3 years ago

3 0

5 minutes until 5, 60 minutes until 6, and 18 minutes until 6:18. that means it is 83 minutes

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Consider rolling two fair dice one 3-sided the other 5-sided

Ne4ueva [31]

Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose

$1\leq x\leq 3,\quad 1\leq y \leq 5$

We have $P(X=x)=\frac{1}{3}$ and $P(Y=y)=\frac{1}{5}$ , because the dice are fair.

Now we use the assumption of independence to claim that

$P(X=x, Y=y) = P(X=x)\cdot P(Y=y) =\dfrac{1}{3}\cdot\dfrac{1}{5} = \dfrac{1}{15}$

Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:

2 in a unique way (1+1)
3 in two possible ways (1+2, 2+1)
4 in three possible ways
5 in three possible ways
6 in three possible ways
7 in two possible ways
8 in a unique way

This implies that the probabilities of the outcomes of $W=X+Y$ are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5