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2 years ago

What’s the word problem... solve it... need help with 7 please! Thanks you

Mathematics

1 answer:

nekit [7.7K]2 years ago

4 0

30. you can model this with an equation and solve, x being the smallest number and the x+1 and x+2 representing the consecutive numbers.

x+(x+1)+(x+2)=93
3x+3=93
3x=90
x=30
x+1=31
x+2=32
30+31+32=93

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An ice cream store sells 28 flavors of ice cream. Determine the number of 4 dip sundaes.

weeeeeb [17]

Answer:

$20,475\ ways$

Step-by-step explanation:

we know that

<u><em>Combinations</em></u> are a way to calculate the total outcomes of an event where order of the outcomes does not matter.

To calculate combinations, we will use the formula

$C(n,r)=\frac{n!}{r!(n-r)!}$

where

n represents the total number of items

r represents the number of items being chosen at a time.

In this problem

$n=28\\r=4$

substitute

$C(28,4)=\frac{28!}{4!(28-4)!}\\\\C(28,4)=\frac{28!}{4!(24)!}$

simplify

$C(28,4)=\frac{(28)(27)(26)(25)(24!)}{4!(24)!}$

$C(28,4)=\frac{(28)(27)(26)(25)}{(4)(3)(2)(1)}$

$C(28,4)=20,475\ ways$

6 0

2 years ago

Solve irrational equation pls

rusak2 [61]

$\hbox{Domain:}\\
x^2+x-2\geq0 \wedge x^2-4x+3\geq0 \wedge x^2-1\geq0\\
x^2-x+2x-2\geq0 \wedge x^2-x-3x+3\geq0 \wedge x^2\geq1\\
x(x-1)+2(x-1)\geq 0 \wedge x(x-1)-3(x-1)\geq0 \wedge (x\geq 1 \vee x\leq-1)\\
(x+2)(x-1)\geq0 \wedge (x-3)(x-1)\geq0\wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle1,\infty) \wedge x\in(-\infty,1\rangle \cup\langle3,\infty) \wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle3,\infty)$

$
\sqrt{x^2+x-2}+\sqrt{x^2-4x+3}=\sqrt{x^2-1}\\
x^2-1=x^2+x-2+2\sqrt{(x^2+x-2)(x^2-4x+3)}+x^2-4x+3\\
2\sqrt{(x^2+x-2)(x^2-4x+3)}=-x^2+3x-2\\
\sqrt{(x^2+x-2)(x^2-4x+3)}=\dfrac{-x^2+3x-2}{2}\\
(x^2+x-2)(x^2-4x+3)=\left(\dfrac{-x^2+3x-2}{2}\right)^2\\
(x+2)(x-1)(x-3)(x-1)=\left(\dfrac{-x^2+x+2x-2}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-x(x-1)+2(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-(x-2)(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\dfrac{(x-2)^2(x-1)^2}{4}\\
4(x+2)(x-3)(x-1)^2=(x-2)^2(x-1)^2\\$
$
4(x+2)(x-3)(x-1)^2-(x-2)^2(x-1)^2=0\\
(x-1)^2(4(x+2)(x-3)-(x-2)^2)=0\\
(x-1)^2(4(x^2-3x+2x-6)-(x^2-4x+4))=0\\
(x-1)^2(4x^2-4x-24-x^2+4x-4)=0\\
(x-1)^2(3x^2-28)=0\\
x-1=0 \vee 3x^2-28=0\\
x=1 \vee 3x^2=28\\
x=1 \vee x^2=\dfrac{28}{3}\\
x=1 \vee x=\sqrt{\dfrac{28}{3}} \vee x=-\sqrt{\dfrac{28}{3}}\\$

There's one more condition I forgot about
$-(x-2)(x-1)\geq0\\
x\in\langle1,2\rangle\\$

Finally
$x\in(-\infty,-2\rangle\cup\langle3,\infty) \wedge x\in\langle1,2\rangle \wedge x=\{1,\sqrt{\dfrac{28}{3}}, -\sqrt{\dfrac{28}{3}}\}\\
\boxed{\boxed{x=1}}$

3 0

2 years ago

Pls help???????? need to have an explanation also

Ratling [72]

Answer:

I would say the answer is 40 cookies

Step-by-step explanation:

The reason I say this is because if you write out the amount of cookies she can make with 6 cups of flour, you would get 30/6. 30 and 6 are both divisible by 6, so if you divided both by 6 you will get 5/1. 1 times 8 is 8, so if you multiply 5 by 8 you will get 40 cookies.

Hope this helped!

7 0

3 years ago

It takes Mike 60 minutes to vacuum a room, and Debbie 45 minutes.

elena55 [62]

Answer:

It takes Mike 15 more minutes to vacuum while it takes Debbie 15 more minutes to wash dishes

Step-by-step explanation:

Explain question properly pls.

3 0

2 years ago

I need help with this question.

aliina [53]

Answer:

answer below

Step-by-step explanation:

in this case the decimal will be recurring so 1 and 2 thirds is 1.6 recurring and 2 and 7 nigths is 2.7 recurring so just plot in between the intervals so the first one could be between 1.6 and 1.7 and the sexond between 2.7 and 2.8

5 0

3 years ago