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Sergeeva-Olga [200]
3 years ago
15

MATH HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Darya [45]3 years ago
8 0

Hi!

One deck of card has 52 cards, and in every deck there are 4 queens.

We will find the probability of pulling out the queen from the deck by diving the number of queens by the number of cards in the deck, like this:

4/52 = 1/13

Hope this helps!

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Help will mark Brainliest!!​
Vedmedyk [2.9K]

Answer:

Subtract 4 from 17, then divide by 3.

Step-by-step explanation:

hope this helps =)

3 0
2 years ago
What is the range of possible sizes for side x? the other two sides are 8.0 and 8.5
kirza4 [7]

Answer: 0.5 < x < 16.5.

Step-by-step explanation:

Given: Two sides of triangle: 8.0 units and 8.5 units

Measure of third side = x

According to the triangle's inequality,

  • Sum of any two sides > third side.    (i)
  • Difference between the sides < third side.    (ii)

If x is the third side, then

x < 8+8.5   [Using (i)]

i.e. x< 16.5  

Also, x > 8.5-8   [Using (ii)]

i.e. x> 0.5

Hence, Range of possible sizes for side x would be 0.5 < x < 16.5.

8 0
3 years ago
Which expressions are equivilent to -4 2/7 + (-1 1/2) + (-3/7)
nika2105 [10]
Is this a multi question ? If so
Please post full question to get full answer

Thank You :)

8 0
3 years ago
I don't understand this. Please help!:::: Provide an answer for a, b, c, and d.
OleMash [197]
Answer for part A is  \angle A \cong \angle D which in English means "angle A is congruent to angle D"

The reason why we know that angle A and angle D are congruent is because they are both right angles. By the right angle congruence theorem (the reason just below the blank for part A), we can say that angle A = angle D. They are both 90 degree angles. 

------------------------------------------------
Answer for the blank in part B is "Given" without quotation marks of course. This is the first "given" while the second given is coming up in part C

------------------------------------------------
For part C, the other given is \angle C \cong \angle F so that's what will go in the blank. It may seem silly, but all we're doing is repeating verbatim what is given to us. With any proof, you always start with what you are given and somehow connect it with what you're trying to prove

------------------------------------------------
Finally, the answer for the blank in part D is "AAS Congruence Theorem" (without quotes)

The AAS congruence theorem allows us to prove two triangles congruent if we know if two pairs of angles are congruent plus if we know two sides are congruent as well.

The angle portions are covered by part A and part C. The side portions are part B's territory. Combining A, B, & C allows us to use the AAS theorem

Note: It is NOT the ASA theorem because the two angles do not sandwich the sides. In other words, the side AB is not between the two angles A and C. Similarly, DE is not between the two angles D and F. The order is very important as ASA is slightly different than AAS. 

8 0
3 years ago
Evaluate the function f(x)=2x-2 when x equals negative 1<br> A. -4<br> B. -3<br> C. 0<br> D. 4
Alona [7]
F(x)= -4. 
Just plug in -1 for your x in 2x-2 and solve like a normal equation. Think of f(x) a your y because that's basically what it is. If it helps, the equation is basically:
y=2x-2 so you would just solve for y by plugging in -1 into x.
8 0
3 years ago
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