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puteri [66]
3 years ago
6

What do the significant figures in a measurement include

Mathematics
1 answer:
Olin [163]3 years ago
8 0
All the digits that are known precisely plus one last digit that is estimated your welcome

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valentinak56 [21]

Answer: 4.08x2

Step-by-step explanation:

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In the picture below, what is the approximate area that is shaded blue?
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I think it’s C sorry if I’m wrong

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Flauer [41]

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3 years ago
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What is 28+42+6,000,000,000
Dimas [21]

Answer:

6,000,000,070

Step-by-step explanation:

6 0 0 0 0 0 0 0 0 0

 +                       2  8

                          <u> 4  2</u>

<u> 6  0 0 0 0 0 0 0 7 0</u>

<u />

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7 0
4 years ago
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Five males with an​ X-linked genetic disorder have one child each. The random variable x is the number of children among the fiv
Dahasolnce [82]

Answer and Explanation:

Given : Five males with an​ X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the​ X-linked genetic disorder.

To find :

a. Does the table show a probability distribution?

b. Find the mean and standard deviation of the random variable x.

Solution :

a) To determine that table shows a probability distribution we add up all six probabilities if the sum is 1 then it is a valid distribution.

\sum P(X)=0.029+0.147+0.324+0.324+0.147+0.029

\sum P(X)=1

Yes it is a probability distribution.

b) First we create the table as per requirements,

x      P(x)         xP(x)           x²            x²P(x)

0    0.029         0              0                0

1     0.147        0.147           1              0.147

2    0.324       0.648         4              1.296

3    0.324       0.972         9              2.916

4    0.147        0.588        16              2.352

5    0.029       0.145         25            0.725

   ∑P(x)=1      ∑xP(x)=2.5               ∑x²P(x)=7.436

The mean of the random variable is

\mu=\sum xP(x)=2.5

The standard deviation of the random sample is

Variance=\sigma^2

\sigma^2=\sum x^2P(x)-\mu^2

\sigma^2=7.436-(2.5)^2

\sigma^2=7.436-6.25

\sigma^2=1.186

\sigma=\sqrt{1.186}

\sigma=1.08

Therefore, The mean is 2.5 and the standard deviation is 1.08.

5 0
3 years ago
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