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vfiekz [6]
3 years ago
12

For the past three months Grace used her cell phone for 43 minutes 62 minutes and 57 minutes how many minutes would you have to

use her cell phone this month for the average usage over the four months to be 55 minutes
Mathematics
1 answer:
RSB [31]3 years ago
5 0

Answer:

Grace should use her phone for 58 minutes to maintain an average of 55 minutes.

Step-by-step explanation:

Usage of first month = 43 minutes

Second month = 62 minutes

Third Minutes = 57 minutes

Let, the usage of fourth month =  k minutes

Mean of the data = 5 minutes

Now, Average of a Data =  \frac{\textrm{Sumof observations}}{\textrm{Total number of observations}}

⇒55 = \frac{43 + 62 + 57 + k}{4}

or, 55  x 4 = 162 + k

⇒    220 - 162  = k

or, k = 58 minutes

So, Grace should use her phone for 58 minutes to maintain an average of 55 minutes.

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Suppose a baseball team has 14 players on the roster who are not members of the pitching staff. Of those 14 players, assume that
Nadusha1986 [10]

Answer: Our required probability would be 0.70.

Step-by-step explanation:

Since we have given that

Number of players = 14

Number of players have recently taken a performance enhancing drug = 3

Number of players have not recently taken a performance enhancing drug = 14-3=11

Number of members chosen randomly = 5

We need to find the probability that at least one of the tested players is found to have taken a performance enhancing drug.

P(Atleast 1) = 1 - P(none is found to have taken a performance enhancing drug)

So, P(X≥1)=1-P(X=0)

P(X\geq 1)=1-^5C_0(\dfrac{11}{14})^5\\\\P(X\geq 1)=1-(0.786)^5\\\\P(X\geq 1)=0.70

Hence, our required probability would be 0.70.

7 0
3 years ago
Name the algebraic property demonstrated in the example below.
VikaD [51]
The algebraic expression x • y • z = y • x • z exhibits the transitive property. Transitive property is applied when rearranging the elements or numbers within a term such that the answer or value is still the same. Transitive property is useful in factoring procedure.
3 0
3 years ago
NEED ASAP
Gala2k [10]

Answer:

(- 2, 4 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) , then the midpoint is

( \frac{x_{1}+x_{2}  }{2} , \frac{y_{1}+y_{2}  }{2} )

Here (x₁, y₁ ) = A (4, 6 ) and (x₂, y₂ ) = B (- 8, 2 )

midpoint = ( \frac{4-8}{2} , \frac{6+2}{2} ) = ( \frac{-4}{2} , \frac{8}{2} ) = (- 2, 4 )

6 0
3 years ago
Read 2 more answers
Please help! also please explain how to solve
iris [78.8K]

Answer:

C

Step-by-step explanation:

The fast way: Testing the options!

Teacher loving way:

An= d×n + A0

d= A4-A3=A5-A4=A6-A5...= 6

A3= 0 = 6×3 + A0

A0= -18

Then the equation is: An= 6n - 18

4 0
2 years ago
Find derivative problem<br> Find B’(6)
dalvyx [7]

Answer:

B^\prime(6) \approx -28.17

Step-by-step explanation:

We have:

\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]

We can move the constant outside:

\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]

Now, we will utilize the product rule. The product rule is:

(uv)^\prime=u^\prime v+u v^\prime

We will let:

\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t

Then:

\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1

(The derivative of u was determined using the chain rule.)

Then it follows that:

\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}

Therefore:

\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]

By simplification:

\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

5 0
3 years ago
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