You have to be at least 16 years old.
First, we need to take the integral of ∛x+2 which is the same as x^1/3+2. To integrate the first part, we add one to the exponent and multiply by the new exponent's reciprocal to get 3/4*x^4/3. Then, the 2 would become a 2x. Now, we are finding the value of 3/4*x^4/3+2x from -1 to 1. To do this, you plug in the top value (1) first, and then subtract the result of plugging in the lower value (-1): [3/4*1^4/3+2(1)]-[3/4*(-1)^4/3+2(-1)]. This would be simplified to [3/4+2]-[3/4-2]. After distributing the negative, it becomes 3/4+2-3/4+2 or simply 4.
I hope this helps
1st, let's calculate the side AB = c in applying the law of cosine:
AC² = BC²+AC² - 2AB.BC. cos87°)
c²= 10.1²+9.8²-2(10.1)(9.8)(cos(87)
c²=102.01 + 96.04 -196.96cos(87)
c² = 187.74 and c = 13.7
Having calculated the 3rd side, now we can apply Heron's formula for the area:
AREA = √p(p-a)(p-b)(p-c), where p is half the perimeter or p=(a+b+c)/2 =16.8
AREA = √16.8(16.8-10.1)(16.8-9.8)(16.8-13.7)
AREA = 49.42 OR 49.4 unit²
