Clearly, an IV solution of D5W (5% dextrose in water) is a clear solution, not light yellow. The nurse should check the patient's chart if the IV fluid ordered is really D5W. If it is confirmed that D5W is the IV fluid of the patient, then the nurse should replace the IV bag with a new one with clear contents and make an entry in the chart about what was observed and why the previous bag was replaced.
The part of the cell would she use as a source of these enzymes is the mitochondrial matrix. It contains <span>he mitochondria's </span>DNA<span>, </span>ribosomes<span>, soluble </span>enzymes<span>, small organic molecules, nucleotide cofactors, and </span>inorganic ions<span>. Thank you for posting your question here. I hope the answer helps. </span>
Could you please add the choices, so I can use those?
Auditory
Temporal lobe is associated with hearing.
Answer:
The population is not following the Hardy-Weinberg equilibrium.
Explanation:
Hardy-Weinberg proposed that the population will remain in the equilibrium if they are not affected with the external natural force like genetic drift, mutation and many others. The gene pool of a population will remain in equilibrium state for generations.
The mathematical expression for the Hardy-Weinberg are
Genotypic frequency is p²+q²+2pq=1
Allele frequency is p+q=1
where p-dominant allele,
q-recessive allele
Therefore,calculating expected frequency of allele q,
q² (recessive genotype)- q²+2pq/1000
= 22+188/1000
=210/1000
= 0.21
q= 0.45
Calculating expected frequency of allele p,
Using p+q=1
p=1-q
p= 0.55 (expected)
Calculating observed value of frequency of p,
p²= p²+2pq/1000
= 790+188/1000
= 978/1000
= 0.978
p = 0.988 (observed)
Since the expected frequency does not match the observed frequency therefore the population is not under the Hardy-Weinberg equilibrium and the gene pool is disturbed.
