A. Because you would have to find the common denominator, which in this case is 24. You would change 2 1/3 to 2 8/24, 1 1/8 to 1 3/24 and 1 3/4 to 1 18/24. Add these all up and you get 5 5/24.
Answer:
C. 342
Step-by-step explanation:
This year, 150% of last year's tickets were sold.
Last year, 228 tickets were sold.
150% as a fraction is 150/100
To find the amount of tickets sold this year, we take the 150/100 and multiply it by 228:
150/100*228= 342 tickets
Your answer is going to be
(×+4) times (×+3)
Hope that helps you.
Answer:
The domain and range of this relationship is (-∞,∞) and (-∞,∞) respectively.
Step-by-step explanation:
We are given that Carly is traveling to visit family.
She drive distance on first day = x
She drive distance on second day = y
We are also given that Carly is travelling a total of 800 miles.
So,x+y=800
We are supposed to find domain and range of this relationship.
y=800-x
Domain : (-∞,∞)
Range:(-∞,∞)
Hence the domain and range of this relationship is (-∞,∞) and (-∞,∞) respectively.
This question s incomplete, the complete question is;
The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for 15 hours. The Thompson family's sprinkler was used for 30 hours.
There was a combined total output of 1050 of water. What was the water output rate for each sprinkler if the sum of the two rates was 55L per hour
Answer:
The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
Step-by-step explanation:
Given the data in the question;
let water p rate for Watson family and the Thompson family sprinklers be represented by x and y respectively
so
x + y = 55 ----------------equ1
x = 55 - y ------------------qu2
also
15x + 30y = 1050
x + 2y = 70 --------------equ3
input equ2 into equ3
(55 - y) + 2y = 70
- y + 2y = 70 - 55
y = 15
input value of y into equ1
x + 15 = 55
x = 55 - 15
x = 40
Therefore, The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
