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3 years ago

HELP ASAPPPPP!

Mathematics

1 answer:

zhuklara [117]3 years ago

6 0

Answer:

can you please make the question more clear!

Step-by-step explanation:

i am guessing you are asking if 1/ (2·2) (3+(3.4·5))=

1/ 4+17+3

1/24?

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What is the slope of the line A. 0 B. 1 C. -4 D. Undefined

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Answer:

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Step-by-step explanation:

The line is a vertical line

Vertical lines have an undefined slope

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10. Enter a fraction to 0.93. Use only whole numbers for numerators and denominators.

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Answer:

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Step-by-step explanation:

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What is 15/8 as a mixed number

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Question 2c: Which dog sitting service is better if you need 5 hours of service? Explain your answer PLEASE!

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3 years ago

Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

3 0

3 years ago