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ozzi
3 years ago
8

HELP ASAPPPPP!

Mathematics
1 answer:
zhuklara [117]3 years ago
6 0

Answer:

can you please make the question more clear!

Step-by-step explanation:

i am guessing you are asking if 1/ (2·2) (3+(3.4·5))=

1/ 4+17+3

1/24?

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9. John drives a total of 16.5 miles to and from his friend's house. He visited his friend
Alina [70]
The answer is d he traveled 198 miles over the span of 12 months driving to his friends house.
8 0
3 years ago
Use the properties of logarithms to prove log, 1000 = log2 10.
Leto [7]

Given:

Consider the equation is:

\log_81000=\log_210

To prove:

\log_81000=\log_210 by using the properties of logarithms.

Solution:

We have,

\log_81000=\log_210

Taking left hand side (LHS), we get

LHS=\log_81000

LHS=\dfrac{\log 1000}{\log 8}                  \left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]

LHS=\dfrac{\log (10)^3}{\log 2^3}

LHS=\dfrac{3\log 10}{3\log 2}                   [\because \log x^n=n\log x]

LHS=\dfrac{\log 10}{\log 2}

LHS=\log_210                    \left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]

LHS=RHS

Hence proved.

6 0
3 years ago
I don’t know how to set this up
kodGreya [7K]

Answer:

9

Step-by-step explanation:

Set it up as the following -

3:8 = x:24.

Now cross multiply - 3 * 24 = 8x

72 = 8x

Now divide both sides by 8.

9 = x

4 0
3 years ago
If laura bought 2.1 pounds of apples is the price per pound of apples greater than or less than $1? How can you tell?
krok68 [10]

Answer

greater than $1.

Step-by-step explanation:

the price of apples per pound is $1.37, therefore, the price per pound of apples is greater than $1.

6 0
2 years ago
Read 2 more answers
Find S18 for geometric series given a5=-6 and a2= -48
Ganezh [65]

an = a1r^(n-1)

a5 = a1 r^(5-1)

-6 =a1 r^4


a2 = a1 r^(2-1)

-48 = a1 r


divide

-6 =a1 r^4

----------------    yields   1/8 = r^3      take the cube root  or each side

-48 = a1 r                     1/2 = r


an = a1r^(n-1)

an = a1 (1/2)^ (n-1)

-48 = a1 (1/2) ^1

divide by 1/2

-96 = a1


an = -96 (1/2)^ (n-1)


the sum

Sn = a1[(r^n - 1/(r - 1)]

S18 = -96 [( (1/2) ^17 -1/ (1/2 -1)]

       =-96 [ (1/2) ^ 17 -1 /-1/2]

      = 192 * [-131071/131072]

 approximately -192

     

       

     

3 0
3 years ago
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