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3 years ago

Can some one please help me with this problem?

Mathematics

2 answers:

Nostrana [21]3 years ago

8 0

(6×90)+(2×50)=$640

$640 was collected on opening night

Lady bird [3.3K]3 years ago

6 0

6a+2s=x (total amount of money)
6 (90)+2 (50)= x
540+100=640
The total amount of money is $640
hope that helps!

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coldgirl [10]

Answer:

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Step-by-step explanation:

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3 years ago

I dont understand this I need to show work to. Please help me.

ra1l [238]

Answer:

a. m = Vd

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Step-by-step explanation:

a. you need to rearrange the equation so that you're solving for m. you can do so by multiplying both sides by V so you end up with

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Answer:

0.80
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0.20
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Step-by-step explanation:

Given:

$P(S\cap F)=0.44\\P(S\cap F^{c})=0.13\\P(S^{c}\cap F^{c}) = 0.32\\P(S^{c}\cap F) = 0.11$

The rule of total probability states that:

$P(A) = P(A\cap B) + P(A\cap B^{c})$

Compute the individual probabilities as follows:

$P(S) = P(S\cap F) + P(S\cap F^{c})\\=0.44+0.13\\0.57$

$P(S^{c}) = 1 - P(S)\\=1-0.57\\=0.43$

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Conditional probability of an event A given B is:

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

Compute the value of $P(S|F)$ :

$P(S|F)=\frac{P(S\cap F)}{P(F)}\\=\frac{0.44}{0.55}\\=0.80$

Compute the value of $P(S|F^{c})$

$P(S|F^{c})=\frac{P(S\cap F^{c})}{P(F^{c})}\\=\frac{0.13}{0.45}\\=0.289$

Compute the value of $P(S^{c}|F)$

$P(S^{c}|F)=\frac{P(S^{c}\cap F)}{P(F}\\=\frac{0.11}{0.55}\\=0.20$

Compute the value of $P(S^{c}|F^{c})$

$P(S^{c}|F^{c})=\frac{P(S^{c}\cap F^{c})}{P(F^{c})}\\=\frac{0.32}{0.45}\\=0.711$

3 0

3 years ago

Round 1378 to the nearest thousands

zaharov [31]

Answer:

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Step-by-step explanation:

if you were rounding it would be 1380, 1400, or 1000 because it isn't over 5

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