The theorem is used to prove △ABC≅△DEC is Side-Angle-Side(SAS) theorem
The two triangles are
△ABC and △DEC
Here we have to prove that the △ABC and △DEC are congruent
It is given that
The length of AC = The length of CD
The angle ACB = The angle ECD
The point C is the midpoint of EB
Therefore,
The length of BC = The length of EC
Therefore, the two sides and one angle of triangle ABC is equal to the two sides and one angle of triangle DEC, so the both triangles are congruent by SAS rule
Hence, the theorem is used to prove △ABC≅△DEC is Side-Angle-Side(SAS) theorem.
Learn more about congruence of triangle here
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A key word to remember when doing this type of math is "SOHCAHTOA".
Sine =
Opposite over
Hypotenuse
Cosine =
Adjacent over
Hypotenuse
Tangent =
Opposite over
Adjacent
Since this is a 3, 4, 5 triangle, with the sides just multiplied by 7, the opposite of A which is 28 would be simplified to 4.
And the Hypotenuse would be simplified to 5.
So, the answer is 4 / 5!
Answer:
A' (8,-7)
B' (8,-7)
When rotating a point 270 degrees counterclockwise about the origin our point A(x,y) becomes A'(y,-x). This means, we switch x and y and make x negative
Step-by-step explanation:
Hope this helps! （づ￣3￣）づ╭❤～
Answer: prob cheatin' on you
Step-by-step explanation: or died-
Answer:
365 degrees :)
Step-by-step explanation:
It's a multiple of 5, but with no zeros, so that means the ones place is 5. The hundreds place is two less than 5, so that's 3. And the tens place is two times the 3, so that gives you 365!
