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3 years ago

HELP!!!!!14. 4e2x – 3 = 12 solve for x leave explination will mark brainliest

1 answer:

Ivan3 years ago

5 0

I will help you but I don't understand the equation. Can you please write it differently. Is it 4^2 x-3=12 or 4^2x - 3 =12

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Prove: Every point of S=(0, 1) is an interior point of S.

myrzilka [38]

Answer:

Proved

Step-by-step explanation:

To prove that every point in the open interval (0,1) is an interior point of S

This we can prove by contradiction method.

Let, if possible c be a point in the interval which is not an interior point.

Then c has a neighbourhood which contains atleast one point not in (0,1)

Let d be the point which is in neighbourhood of c but not in S(0,1)

Then the points between c and d would be either in (0,1) or not in (0,1)

If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.

Then we find that dn is a boundary point of S

But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.

Every point of S=(0, 1) is an interior point of S.

3 0

2 years ago

Can you guys help me answer it

Hitman42 [59]

Answer:

300pi

Step-by-step explanation:

that is 3/4 of a circle with the radius of 20. Meaning that the area is 300pi

8 0

2 years ago

Anthony purchased a T-shirt for $14.95 and a pair of pants for $21.35.

Mashutka [201]

Answer:

Anthony gave the sales clerk $40

Step-by-step explanation:

7 0

3 years ago

Hi there can anyone help me with this question please

forsale [732]

Mean means average, so you would add the numbers up and divide by the amount of numbers in the set.

4 0

3 years ago

Harmonic mean if a number h such that (h-a)/(b-h)=a/b Prove h is H(a,b) iff satisfies either relation a. (1/a)-(1/h) = (1/h) - (

Fudgin [204]

A.

$\displaystyle\frac1a-\frac1h=\frac1h-\frac1b$
$\implies\displaystyle\frac{h-a}{ah}=\frac{b-h}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac{ah}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac ab$

b.

$\displaystyle h=\frac{2ab}{a+b}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{\frac{2ab}{a+b}-a}{b-\frac{2ab}{a+b}}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{2ab-a(a+b)}{b(a+b)-2ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{ab-a^2}{b^2-ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{a(b-a)}{b(b-a)}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac ab$

The other direction can be proved by following the manipulations in the reverse order.

7 0

2 years ago