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Ulleksa [173]
4 years ago
8

A grey turtle lays an average of 10 eggs. If the number of eggs laid never varies from the average by more than five, what is th

e least number of eggs that would be laid by six turtles?
Mathematics
1 answer:
Rudiy274 years ago
7 0
Number of eggs never varies from the average by more than five => the least number that each turtle lays can be 5 => the least number of eggs laid by 6 turtles: 5 (minimum eggs) x 6 (turtles) = 30(eggs) 
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sveticcg [70]
Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that

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For parts (a) and (b), you're given everything you need to determine P(B).

For part (c), if A and B are mutually exclusive, then P(A\cap B)=0, so P(A\cup B)=P(A)+P(B). If the given probability is P(A\cup B)=0.55, then you can find P(B)=0.15. But if this given probability is for the intersection, finding P(B) is impossible.


For part (d), if A and B are independent, then P(A\cap B)=P(A)\cdot P(B).
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Step-by-step explanation:

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