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GrogVix [38]
3 years ago
12

HELP QUICK LOTS OF POINTS

Mathematics
2 answers:
butalik [34]3 years ago
7 0

Answer:

When the sequence of sides (shortest to longest, for example) remains the same (CW or CCW), then the number of reflections

Step-by-step explanation:

Bad White [126]3 years ago
6 0

Answer:

  see attached

Step-by-step explanation:

When the sequence of sides (shortest to longest, for example) remains the same (CW or CCW), then the number of reflections is even, possibly zero. The figure will have been <em>translated</em> if all of the corresponding sides retain their original direction, otherwise <em>rotation</em> is involved.

If the sequence is reversed, as in the upper right and lower left figures, then <em>reflection</em> is involved. The line of reflection will be the line through the midpoints of the segments connecting corresponding vertices.

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The ratio of boys to girls in a class is 3:5. There are 40 students in the class. How many students are girls?
AnnyKZ [126]

Step-by-step explanation:

3+5=8

40÷8=5

5x5=25 girls

5x3=15

5 0
3 years ago
Read 2 more answers
Will give brainliest!
fiasKO [112]
Let's give some distances
100 up 100 flat 100 down meters
then return 100 up 100 flat 100 down


time required (distance/rate = time ) 200/100 + 200/120 + 200 / 150 = 5 hr

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5 0
2 years ago
Round the number 296,386,482 to the nearest million
expeople1 [14]
1,000,000 is 1 million
look at the previous digit
if it is less than 5 then leave the millions place as is and replace the following digits with zeroes

if it is equal to or greater than 5, add 1 to the millions place and replace the following digits with zeroes

296,386,482
3<5
round down (leave as is baseically)
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8 0
3 years ago
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An object is thrown upward from the top of a 48-foot building with an initial velocity of 32 feetquadratic equation h = - 16t^2+
Alex17521 [72]

SOLUTION

The object would hit the ground at the root of the equation, that is where h = 0

So we have

\begin{gathered} h=-16t^2+32t+48=0 \\ -16t^2+32t+48=0 \\ 16t^2-32t-48=0 \\ divide\text{ through by 16} \\ t^2-2t-3=0 \end{gathered}

Solving the quadratic equation, we have

\begin{gathered} t^2-3t+t-3=0 \\ t(t-3)+1(t-3)=0 \\ (t-3)(t+1)=0 \\ t=3,\text{ or} \\ t=-1 \end{gathered}

So we ignore -1 as time cannot be negative.

Hence the object hit the ground in 3 seconds

3 0
1 year ago
Settle a dispute.
alexandr402 [8]

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8 clicks / 4 seconds = 2 clicks per second.

Amir is correct

6 0
2 years ago
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