Pls help with this equation!!!!!!!! plz

A bag contains 10 red, 6 green, 12 orange, and 8 purple candies. Without looking, Ann pulls 1 piece of candy out of the bag. Wha

ZanzabumX [31]

Answer:

<h2>option c.1 /4 ..... totol outcomes =36,,,, favourable outcomes=8,,,,,, probability=8/36====1/4</h2>

8 0

4 years ago

Select all that are equivalent to 3 square root -40 below

lyudmila [28]

Answer:

6 √(10) i (the last option)

and 6i√10

Step-by-step explanation:

√-40 = √4 * √-10 = 2√(10) i

3 * 2√(10) i

= 6 √10 i

Also 6i√10 is equivalent

4 0

4 years ago

Lucas is walking around the edge of the playground shown. How far will lukas have to walk when he finishes one loop around the p

Tanya [424]

Answer:

See Explanation

Step-by-step explanation:

Required

Determine how far he walked in one loop

<em>This question is incomplete, as the playground diagram and dimensions are missing. However, I'll answer on a general terms.</em>

What this question requires is to calculate the perimeter of the playground.

Assume that the playground is rectangular and the dimensions are: 2 meters by 3 meters.

The distance walked will be calculated using the following perimeter formula.

$Distance = 2(2m + 3m)$

$Distance = 2(5m)$

$Distance = 10m$

If it is a square with 5m as the length of one of its side, the distance would be:

$Distance = 4 * 5m$

$Distance = 20m$

<em>So basically, all you need to do is calculate the perimeter of the playground.</em>

7 0

3 years ago

Give this problem a try and try to solve this

tia_tia [17]

Answer:

No solution

Step-by-step explanation:

Given equation is,

$\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}-\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}=0$

$\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}=\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}$

$\frac{(x+1)}{\sqrt{x}(1-x)}+\frac{(\sqrt{x}-1)}{\sqrt{x}(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}$

$\frac{(\sqrt{x}+1)(x+1)+(\sqrt{x}-1)(1-x)}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}$

$\frac{x\sqrt{x}+x+\sqrt{x}+1+\sqrt{x}-1-x\sqrt{x}+x}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2x+2\sqrt{x}}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2(\sqrt{x}+1)}{(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2}{1-x}=(\frac{4+x}{1-x})^\frac{1}{2}$ if x ≠ ±1

$(\frac{2}{1-x})^2=\frac{4+x}{1-x}$ [Squaring on both the sides of the equation]

$\frac{4}{(1-x)}=(4+x)$

4 = (1 - x)(4 + x)

4 = 4 - 4x + x - x²

0 = -3x - x²

x² + 3x = 0

x(x + 3) = 0

x = 0, -3

But both the solutions x = 0 and x = -3 are extraneous solutions, given equation has no solution.

5 0

3 years ago

Read 2 more answers

Can someone please help? :)

garri49 [273]

Answer:

The first step is to find the volume of the two hemispheres.

Step-by-step explanation:

$\boxed{volume \: of \: sphere = \frac{4}{3} \pi {r}^{3} }$

Since the 2 hemispheres have the same radius, we can simply find the volume of a sphere.

Volume of sphere

$= \frac{4}{3}( \pi)( {12}^{3} )$

$= 2304\pi \: in^{3}$

Volume of solid

= volume of cylinder -volume of 2 hemispheres

Let's find the volume of the cylinder.

$\boxed{voume \: of \: cylinder = \pi {r}^{2}h }$

Volume of cylinder

$= \pi( {12}^{2} )(24)$

$= 3456\pi \: in^{3}$

Thus, volume of solid

$= 3456\pi - 2304\pi$

$= 1152\pi$

$= 1152(3.14)$

$= 3617.28 \: in^{3}$

7 0

3 years ago

Read 2 more answers