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r-ruslan [8.4K]
3 years ago
6

at Franklin elementary school 2/3 of all students attended the chorus recital on Thursday. on Friday 3/4 of all the students att

ended the basketball game. which event had the higher attendance?
Mathematics
1 answer:
Sonja [21]3 years ago
4 0
The students on Friday
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If the place these marbles in a bag close your eyes and choose a marble what is the probability that it will be pink?
Sveta_85 [38]

Answer:

3/14

Step-by-step explanation:

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3 0
3 years ago
Shayna's school is selling tickets to a play. On the first day of ticket sales the school sold 13 senior citizen tickets and 13
jasenka [17]

The price of one senior citizen ticket is 8$ and one student ticket is 12$.

<h3>What is the equation?</h3>

The equation is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are equal.

Let the price of one senior citizen ticket = x

And the price of one student ticket = y

Given that, on the first day of ticket sales, the school sold 13 senior citizen tickets and 13 student tickets for a total of $260

The school took in $212 on the second day by selling 13 senior citizen tickets and 9 student tickets.

13x +13y = 260

13x + 9y = 212

Subtract the equation  from first

13x +13y - (13x + 9y) = 260 - 212

4y = 48

y = 48/4

y = 12

Substitute the value of y in the equation 13x + 9y = 212

13x + 9(12) = 212

13x + 108 = 212

13x = 212 - 108

13x = 104

x = 104/13

x = 8

Hence, the price of one senior citizen ticket is 8$ and one student ticket is 12$.

Learn more about the equation here:

brainly.com/question/10413253

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6 0
2 years ago
What is the mean, median, and mode of 33, 37, 37, 39, 42, 43, 46, 48, 50, 52, 55
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3 0
4 years ago
Read 2 more answers
2(x+y) = 61-2y<br> 4x-4 = 18-3y
Naddik [55]

Answer:

x = 8

y = -7

Step-by-step explanation:

This is a system of equations called simultaneous equations. We shall solve it by elimination method Step 1We shall label the equations (1) and (2)−3y−4x=−11.....(1)3y−5x=−61......(2)Step 2Multiply each term in equation (1) by 1 to give equation (3)1(-3y-4x=-11).....(1)-3y-4x=-11....(3)Step 3Multiply each term in equation 2 by -1 to give equation (4)-1(3y−5x=−61)......(2)-3y+5x=61.....(4)Step 4-3y-4x=-11....(3)-3y+5x=61.....(4)Subtract each term in equation (3) from each term in equation (4)-3y-(-3y)+5x-(-4x)=61-(-11)-3y+3y+5x+4x=61+110+9x=729x=72Step 5Divide both sides of the equation by 9, the coefficient of the unknown variable x to find the value of x 9x/9 = 72/9x = 8Step 6Put in x = 8 into equation (2)3y−5x=−61......(2)3y-5(8)=-613y-40=-61Collect like terms by adding 40 to both sides of the equation 3y-40+40=-61+403y=-21Divide both sides by 3, the coefficient of y to find the value of y 3y/3=-21/3y=-7Therefore, the values of x and y that satisfy the equations are 8 and -7 respectively

4 0
3 years ago
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