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USPshnik [31]
3 years ago
8

4. Which property is illustrated by the statement? 8(-5/6)=(-5/6)8

Mathematics
2 answers:
SCORPION-xisa [38]3 years ago
7 0
4. is B
and 5. is also B
nika2105 [10]3 years ago
4 0

Answer:

1) Commutative property for multiplication

2) Commutative property for addition

Step-by-step explanation:

We are given the following information in the question:

We have to identify the properties for addition and multiplication.

Associative Property:

The associative property states that we  can add or multiply regardless of how the numbers are grouped. By grouped we mean how we use parenthesis.

a+(b+c) = (a+b)+c

a\times (b\times c) = (a\times b)\times c

Commutative Property:

Commutative property of addition and multiplication states that changing the order of the operands does not change the result.

a + b = b +a

a\times b = b\times a

1) 8\times \displaystyle\frac{-5}{6} = \displaystyle\frac{-5}{6}\times 8

a\times b = b\times a

This is commutative property for multiplication

2) (3\times 2) + 4 = 4 + (3\times 2)

a + b = b +a

This is commutative property of addition.

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a quantity h varies directly with w and inversely with p. if h = 2, w = 4, and p = 6. what is the constant of variation? 1) 1/12
7nadin3 [17]
Hello,

h=k*w/p; if w=4,and p=6 then h=2
2=k*4/6==>k=2*6/4==>k=3

ANswer C
3 0
4 years ago
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What number needs to be added to make a mean of 80 with the numbers 71 80 and 86
pentagon [3]
80*4=320-(71+80+86)=83 So 83 needs to be added.
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3 years ago
How many roots does a quadratic have if the discriminant if prime?
scZoUnD [109]

"The discriminant is prime?" I haven't heard that one before.

Here are the general rules:

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3. a negative discr. results in two complex roots, which sometimes means two imaginary roots.

5 0
3 years ago
The perimeter of a rectangular park is 500 feet. The length of the park is 100 feet longer than the width. Find the length of th
lord [1]

Answer:

The length of the park is 175 feet

Step-by-step explanation:

Let us solve the question

∵ The perimeter of a rectangular park is 500 feet

∵ The formula of the perimeter of the rectangle is P = 2(L + W)

∵ L is the length and W is the width

→ Equate the rule of the perimeter by 500

∴ 2(L + W) = 500

→ Divide both sides by 2

∴ L + W = 250 ⇒ (1)

∵ The length of the park is 100 feet longer than the width

→ That means L is W plus 100

∴ L = W + 100 ⇒ (2)

→ Substitute L in (1) by (2)

∵ W + 100 + W = 250

→ Add the like terms

∵ (W + W) + 100 = 250

∴ 2W + 100 = 250

→ Subtract 100 from both sides

∵ 2W + 100 - 100 = 250 - 100

∴ 2W = 150

→ Divide both sides by 2

∴ W = 75

→ Substitute the value of W in (2) to find L

∵ L = 75 + 100 = 175

∴ The length of the park is 175 feet

6 0
3 years ago
Directions: Calculate the area of a circle using 3.14x the radius
Leokris [45]

\qquad\qquad\huge\underline{{\sf Answer}}♨

As we know ~

Area of the circle is :

\qquad \sf  \dashrightarrow \:\pi {r}^{2}

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

<h3>Problem 1</h3>

\qquad \sf  \dashrightarrow \:r = d \div 2

\qquad \sf  \dashrightarrow \:r = 4.4\div 2

\qquad \sf  \dashrightarrow \:r = 2.2 \: mm

Now find the Area ~

\qquad \sf  \dashrightarrow \: \pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times  {(2.2)}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times  {4.84}^{}

\qquad \sf  \dashrightarrow \:area  \approx 15.2 \:  \: mm {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>problem 2</h3>

\qquad \sf  \dashrightarrow \:r = d \div 2

\qquad \sf  \dashrightarrow \:r = 3.7 \div 2

\qquad \sf  \dashrightarrow \:r = 1.85 \:  \: cm

Bow, calculate the Area ~

\qquad \sf  \dashrightarrow \: \pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times (1.85) {}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times 3.4225 {}^{}

\qquad \sf  \dashrightarrow \:area  \approx 10.75 \:  \: cm {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>Problem 3 </h3>

\qquad \sf  \dashrightarrow \:\pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times (8.3) {}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times 68.89

\qquad \sf  \dashrightarrow \:area \approx216.31 \:  \: cm {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>Problem 4</h3>

\qquad \sf  \dashrightarrow \:r = d \div 2

\qquad \sf  \dashrightarrow \:r = 5.8 \div 2

\qquad \sf  \dashrightarrow \:r = 2.9 \:  \: yd

now, let's calculate area ~

\qquad \sf  \dashrightarrow \:3.14 \times  {(2.9)}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times  8.41

\qquad \sf  \dashrightarrow \:area  \approx26.41 \:  \: yd {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>problem 5</h3>

\qquad \sf  \dashrightarrow \:r = d \div 2

\qquad \sf  \dashrightarrow \:r = 1 \div 2

\qquad \sf  \dashrightarrow \:r = 0.5 \:  \: yd

Now, let's calculate area ~

\qquad \sf  \dashrightarrow \:\pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times (0.5) {}^{2}

\qquad \sf  \dashrightarrow \:3.14  \times 0.25

\qquad \sf  \dashrightarrow \:area \approx0.785 \:  \: yd {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>problem 6</h3>

\qquad \sf  \dashrightarrow \:\pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times  {(8)}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times 64

\qquad \sf  \dashrightarrow \:area = 200.96 \:  \: yd {}^{2}

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

8 0
2 years ago
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