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leva [86]
3 years ago
11

What is a common factor for the two fractional terms 5/8x and 11/8xy ?

Mathematics
1 answer:
Vaselesa [24]3 years ago
5 0

Answer:1/8x

Step-by-step explanation:

5/8x=5 x 1/8x

11/8xy=11 x 1/8x x 1/y

Therefore the common factor Of The two terms is 1/8x

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a basketball player through the ball vertically in the air. the height h of the ball after time t is given by the quadratic func
Flauer [41]
I think yes he did in ball rolling in throw the ball 5_t+7t. yes maybe in be ball player in won
4 0
3 years ago
A bag contains red marbles, white marbles, and blue marbles. Randomly choose two marbles, one at a time, and without replacement
dsp73

Answer:

P(First\ White\ and\ Second\ Blue) = \frac{3}{28}

P(Same) = \frac{67}{210}

Step-by-step explanation:

Given (Omitted from the question)

Red = 7

White = 9

Blue = 5

Solving (a): P(First\ White\ and\ Second\ Blue)

This is calculated using:

P(First\ White\ and\ Second\ Blue) = P(White) * P(Blue)

P(First\ White\ and\ Second\ Blue) = \frac{n(White)}{Total} * \frac{n(Blue)}{Total - 1}

<em>We used Total - 1 because it is a probability without replacement</em>

So, we have:

P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{21 - 1}

P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{20}

P(First\ White\ and\ Second\ Blue) = \frac{9*5}{21*20}

P(First\ White\ and\ Second\ Blue) = \frac{45}{420}

P(First\ White\ and\ Second\ Blue) = \frac{3}{28}

Solving (b) P(Same)

This is calculated as:

P(Same) = P(First\ Blue\ and Second\ Blue)\or\ P(First\ Red\ and Second\ Red)\ or\ P(First\ White\ and Second\ White)

P(Same) = (\frac{n(Blue)}{Total} * \frac{n(Blue)-1}{Total-1})+(\frac{n(Red)}{Total} * \frac{n(Red)-1}{Total-1})+(\frac{n(White)}{Total} * \frac{n(White)-1}{Total-1})

P(Same) = (\frac{5}{21} * \frac{4}{20})+(\frac{7}{21} * \frac{6}{20})+(\frac{9}{21} * \frac{8}{20})

P(Same) = \frac{20}{420}+\frac{42}{420} +\frac{72}{420}

P(Same) = \frac{20+42+72}{420}

P(Same) = \frac{134}{420}

P(Same) = \frac{67}{210}

6 0
3 years ago
Find the zeros of the following<br> please solve step by step<br> 1. x³+9x²+26x+24=0
Vlad1618 [11]

Answer: -4, -3, -2

Step-by-step explanation:

By inspection, we know x=-2 is a root.

We can thus rewrite the equation as

(x+2)\left(\frac{x^3 + 9x^2 + 26x+24}{x+2} \right)=0\\\\(x+2)(x^2 + 7x+12)=0\\\\(x+2)(x+3)(x+4)=0\\\\x=-4, -3, -2

3 0
2 years ago
Help! Best answer gets brainliest!
liraira [26]

Answer:

11

Step-by-step explanation:

because the length of 12 is the same of t+1 so 11+1=12

youre welcome

6 0
3 years ago
Read 2 more answers
48 inches long and 24 inches wide. What is the area of the poster in square feet?
liraira [26]
Hi there! We just need to use some simple multiplication for this equation. I'll walk you through it.

Remember that 1 foot is 12 inches. This'll come in handy later.

48 * 24 = 1152

Now, divide this by 12.

1152/12 = 96

There you go! The area of the poster is 96 square feet.

:)
5 0
3 years ago
Read 2 more answers
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