The differnce of 2 perfect cubes
remember
a³-b³=(a-b)(a²+ab+b²)
so
remember
a³-b³=(a-b)(a²+ab+b²)
so
Simplify. (2x^2-5x+3) - (-x^2+4x-5)
2 answers:
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The possible digits are: 5, 6, 7, 8 and 9. Let's mark the case when the locker code begins with a prime number as A and the case when <span>the locker code is an odd number as B. We have 5 different digits in total, 2 of which are prime (5 and 7).
First propability:
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<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with 5, 7 or 9 (three of five digits).
Second probability:
</span>
First propability:
</span>
<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with 5, 7 or 9 (three of five digits).
Second probability:
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