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hammer [34]
3 years ago
11

The weight of outlet boxes is proportional to the volume of boxes involved. if 400 boxes weigh 120 pounds, how much would 500 bo

xes weigh?
Mathematics
1 answer:
stiks02 [169]3 years ago
3 0
400=120 120+120=240 500=120  your answer is 240
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A members-only speaker series allows people to join for $21 and then pay $2 for every event attended. What is the maximum number
pashok25 [27]
2 because if you add 4 dollars to it is is 25$ and that is equal it 2 events
8 0
3 years ago
Read 2 more answers
Suppose that x and y are both differentiable functions of t and are related by the given equation. Use implicit differentiation
stepan [7]

Answer:

Let z = f(x, y) where f(x, y) =0 then the implicit function is

\frac{dy}{dx} =\frac{-δ f/ δ x }{δ f/δ y }

Example:- \frac{dy}{dx}  = \frac{-(y+2x)}{(x+2y)}

Step-by-step explanation:

<u>Partial differentiation</u>:-

  • Let Z = f(x ,y) be a function of two variables x and y. Then

\lim_{x \to 0} \frac{f(x+dx,y)-f(x,y)}{dx}    Exists , is said to be partial derivative or Partial differentiational co-efficient of Z or f(x, y)with respective to x.

It is denoted by δ z / δ x or δ f / δ x

  • Let Z = f(x ,y) be a function of two variables x and y. Then

\lim_{x \to 0} \frac{f(x,y+dy)-f(x,y)}{dy}    Exists , is said to be partial derivative or Partial differentiational co-efficient of Z or f(x, y)with respective to y

It is denoted by δ z / δ y or δ f / δ y

<u>Implicit function</u>:-

Let z = f(x, y) where f(x, y) =0 then the implicit function is

\frac{dy}{dx} =\frac{-δ f/ δ x }{δ f/δ y }

The total differential co-efficient

d z = δ z/δ x +  \frac{dy}{dx} δ z/δ y

<u>Implicit differentiation process</u>

  • differentiate both sides of the equation with respective to 'x'
  • move all d y/dx terms to the left side, and all other terms to the right side
  • factor out d y / dx from the left side
  • Solve for d y/dx , by dividing

Example :  x^2 + x y +y^2 =1

solution:-

differentiate both sides of the equation with respective to 'x'

2x + x \frac{dy}{dx} + y (1) + 2y\frac{dy}{dx} = 0

move all d y/dx terms to the left side, and all other terms to the right side

x \frac{dy}{dx}  + 2y\frac{dy}{dx} =  - (y+2x)

Taking common d y/dx

\frac{dy}{dx} (x+2y) = -(y+2x)

\frac{dy}{dx}  = \frac{-(y+2x)}{(x+2y)}

7 0
3 years ago
Solve by graphing.
const2013 [10]

Answer:

(4,4)

Step-by-step explanation:

y = 2x - 4 -------eqn 1

4y = x + 12 ------eqn 2

From eqn 1 y = 2x - 4; insert in eqn 2

4 (2x-4) = x + 12 (open the bracket)

8x - 16 = x + 12 (taking like figures to the same side, sign changes)

8x - x = 12 + 16

7x = 28

x = 28/7

x = 4

From eqn 1

y = 2x - 4

y = 2(4) - 4

y = 8 - 4

y = 4

(x,y) = (4,4)

8 0
3 years ago
What is t+16 for +=-5
Lady bird [3.3K]

Answer:

9

Step-by-step explanation:

just do 16 - 5 its exactly the same

5 0
3 years ago
9x2/3 help due in 3 min
sattari [20]

Answer:

6

Step-by-step explanation:

9/1 × 2/3

(9 × 2 = 18)

(1 × 3 = 3)

18 ÷ 3 = 6

7 0
3 years ago
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