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stellarik [79]
3 years ago
12

Rewrite the radical expression as an expression with a rational exponent. pls help

Mathematics
2 answers:
Masja [62]3 years ago
7 0

Answer:

\sqrt[7]{x^{3} }= x^{\frac{3}{7} }

Step-by-step explanation:

In order to solve this question we need to understand the following.

\sqrt{x} = x^{\frac{1}{2} }

\sqrt[3]{x}  = x^{\frac{1}{3} }

\sqrt[4]{x}= x^{\frac{1}{4} }

(Notice that the numerator of the fraction is the power of the x that is being squared)

If you need proof here it is.....

\sqrt{x} = x^{\frac{1}{2} }

(\sqrt{x} )^{2} = (x^{\frac{1}{2} } )^{2}

x = x

Now that we got that out of the way we can rewrite \sqrt[7]{x^{3} } as........

\sqrt[7]{x^{3} }= x^{\frac{3}{7} }

olga nikolaevna [1]3 years ago
3 0

Answer:

come on baexz f** me in 69

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algol [13]
To simplify this, you would have to turn b^-2 into a positive exponent.
To do this, we have to flip b^-2, which would get rid of the negate from the exponent: -2

3a^4 b^-2 c^3 / b^-2

Then we get the answer:

3a^4 c^3
------------
   b^-2

I have a picture to clarify! 
I hope this helped, let me know if you don't understand! ^.^

6 0
2 years ago
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liberstina [14]

Answer:

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Step-by-step explanation:

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9)  (4 root 2)^5 = 2^(5/4)

10) (4 root 5)^5 = 5^(5/4)

5 0
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8 0
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Step-by-step explanation:

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