c=52, a=2b+8
<span>
Pythagorean Theorem = a^2+b^2=c^2</span>
<span>
(2b+8)^2+b^2=52^2</span>
<span>
<span>
4b^2+32b+64+b^2=2704</span></span>
<span><span>
5b^2+32b-2640=0 </span></span>
<span>
b=20 </span>
a= 2(20)+8 =
48
<span>48+20+52
= 120</span>
142=120% of x
120% of x= 1.2x
142=1.2x
142/1.2 = 1.2x/1.2
x= 118.33
The unknown number should be 118.33, rounded to 118 or so.
In order to get who was right we need to solve the expression:
2a^2b(-2ab^3)^-2
The above can be written as fraction to get:
(2a^2b)/(-2ab^3)^2
=(2a^2b)/(4a^2b^6)
=1/2(a^(2-2)b^(1-6))
=1/2a^0b^-5
=1/2b^(-5)
This implies that neither of the was right
Answer:
s = 268.27
Step-by-step explanation:
simplify: 75+19547-11s=16671
simplify more: 19622-11s=16671
subtract 19622 on both sides: -11s=-2951
divide both sides by -11: s=268.27
Answer:
The 96th term of the arithmetic sequence is -1234.
Step-by-step explanation:
first term (a)=1
second term (t2)=-12
common difference (d)= t2-a
d=-12-1
d=-13
96th term (t96)=?
We know that,
t96=a+(n-1)d
t96=1+(96-1)(-13)
t96=1+95(-13)
t96=1-1235
t96=-1234
