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3 years ago

The function f(x)=−3x+2 is defined over the domain −1

Mathematics

1 answer:

DENIUS [597]3 years ago

7 0

Answer:

Yes.

Step-by-step explanation:

$f\left(x\right)=-3x+2$

$f\left(-1\right)=-3(-1)+2$

$y=f(-1)=5$

The domain of this function is all Real numbers $\:\left(-\infty \:,\:\infty \:\right)$

$\{x \in \mathbb{R}: -\infty \:$

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A recipe that serves 8 calls for 2 ½ cups of flour. How many cups of flour should you use if you want to adjust the recipe to ma

avanturin [10]

Answer:

3 3/4 cups of flour

Step-by-step explanation:

Write and solve an equation of ratios, as follows:

8 2.5 cups

------- = ----------------

12 c

3 3/4 cups of flour to adjust the receipt as described.

7 0

3 years ago

Read 2 more answers

Which of the quadratic functions has the narrowest graph?

topjm [15]

A quadratic function's graph being wide or narrow is determined or depended on a-term:

$\large{y = a {x}^{2} + bx + c}$

If |a| has a lot of value, for example a = 2 or a = 100. The graph will get narrower if increasing the value of |a|. On the other hand, If |a| has small value, for example a = 1/2 or a = 1/10000. The graph would be wide.

Also it does not matter if a-term is negative or not since a-term being positive or negative determines if a parabola is upward or downward. Only |a| determines how narrow/wide the graph is.

From the question, it is clear that the parabola y = 2x^2 is the narrowest graph since it has the highest |a| value out of all choices.

Answer

y = 2x^2

6 0

3 years ago

What is the sum of the series? ∑ i=1 5 4i Enter your answer in the box.

nekit [7.7K]

We have that

the expressions is <span>∑ i=1 to 5 (4i)
for i=1-----------> (4*1)=4
</span>for i=2-----------> (4*2)=8
for i=3-----------> (4*3)=12
for i=4-----------> (4*4)=16
for i=5-----------> (4*5)=20
∑ i=1 to 5 (4i)=[4+8+12+16+20]=60

the answer is 60

7 0

3 years ago

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F(x)=-x^2+1 find f(-3)

Serjik [45]

Answer:

-8

Step-by-step explanation:

All you have to do to solve this equation is plug "-3" into the equation where you see "x"

$f(x)=-x^2+1\\f(-3)=-(-3)^2+1\\f(-3)=-(9)+1\\f(-3)=-9+1\\f(-3)=-8$