Answer:
The answer to this equation is 7.5
Step-by-step explanation:
What I did is started with PEMDAS:
6÷2 (1 + 2) ÷4 (4 + 5) ÷ 6
^ ^
(3) (9)
Now the 3 and the 9 are what are in the ()
6÷2 = 3... 3 (3) = 9.
9 ÷ 4 = 5.
The 9 from earlier is still in parenthesis...
Take 5 and the 9 in parenthesis and multiply (If a single number is in (), It means to multiply anyway)
5 (9) = 45
The Final Step is to divide by 6
45 ÷ 6 = (FINAL) 7.5
<em>I hope this helped! (:</em>
I believe it’s B since both A and B are the same angle so the rest wouldn’t make sense
<u><em>Answer:</em></u>The factored form is: (x-2)(x-4) = 0
<u><em>Explanation:</em></u>To factor an expression, we need to <u>get its solutions</u>.
<u>The standard form of the quadratic equation is:</u>
ax² + bx + c = 0
<u>The given equation is:</u>
x² - 6x + 8 = 0
<u>By comparison:</u>
a = 1
b = -6
c = 8
Now, to get the roots, we will substitute with the values of a, b and c in the quadratic formula shown in the attached image.
<u>This will give us:</u>
either x =
![\frac{6+ \sqrt{(-6)^2-4(1)(8)} }{2(1)} = 4](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%2B%20%5Csqrt%7B%28-6%29%5E2-4%281%29%288%29%7D%20%7D%7B2%281%29%7D%20%3D%204)
This means that
the first factor is (x-4)
or x =
![\frac{6- \sqrt{(-6)^2-4(1)(8)} }{2(1)} = 2](https://tex.z-dn.net/?f=%20%5Cfrac%7B6-%20%5Csqrt%7B%28-6%29%5E2-4%281%29%288%29%7D%20%7D%7B2%281%29%7D%20%3D%202)
This means that
the second factor is (x-2)
Based on the above, the factored form would be:
(x-4)(x-2) = 0
Hope this helps :)
Answer:
945 is your answer!
Step-by-step explanation:
(25 x 30) + 195
(750) + 195
945
The solution is: x=2, y=-2
Step-by-step explanation:
Given equations are:
6x+2y=8 Eqn 1
12x+y=22 Eqn 2
Multiplying Eqn 1 by 2
Eqn 3
Subtracting Equation 2 from eqn 3
![12x+4y-(12x+y)=16-22\\12x+4y-12x-y=-6\\3y=-6\\Dividing\ both\ sides\ by\ 3\\\frac{3y}{3}=\frac{-6}{3}\\y=-2](https://tex.z-dn.net/?f=12x%2B4y-%2812x%2By%29%3D16-22%5C%5C12x%2B4y-12x-y%3D-6%5C%5C3y%3D-6%5C%5CDividing%5C%20both%5C%20sides%5C%20by%5C%203%5C%5C%5Cfrac%7B3y%7D%7B3%7D%3D%5Cfrac%7B-6%7D%7B3%7D%5C%5Cy%3D-2)
Putting y=-2 in eqn 2
![12x-2=22\\Adding\ 2\ on\ both\ sides\\12x-2+2=22+2\\12x=24\\Dividing\ both\ sides\ by\ 12\\\frac{12x}{12} = \frac{24}{2}\\x=2](https://tex.z-dn.net/?f=12x-2%3D22%5C%5CAdding%5C%202%5C%20on%5C%20both%5C%20sides%5C%5C12x-2%2B2%3D22%2B2%5C%5C12x%3D24%5C%5CDividing%5C%20both%5C%20sides%5C%20by%5C%2012%5C%5C%5Cfrac%7B12x%7D%7B12%7D%20%3D%20%5Cfrac%7B24%7D%7B2%7D%5C%5Cx%3D2)
The solution is: x=2, y=-2
Keywords: Linear equations, Elimination Method
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