Answer:
No.
Step-by-step explanation:
It has different order of matrices .
For <em>A</em><em>d</em><em>d</em><em>i</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em>or <em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>r</em><em>a</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em>, both matrices must have the same number of <u>r</u><u>o</u><u>w</u><u>s</u> and <u>c</u><u>o</u><u>l</u><u>u</u><u>m</u><u>n</u><u>s</u> .
Answer:
what is the question
Step-by-step explanation:
Questions for answers
Answer:
b/(1/4)(f)=a
Step-by-step explanation:
b=1/4af
b/(1/4)(f)=a
So you first multiply the fractions: 2/5 times -1/5 = -2/25; then the a's: a^2 times a equals a^3; then multiply the x's: x times x^2 equals x^3.
The answer would be -2/25a^3x^3
The answer to this is 150.