Can any one figure this out?

Mathematics

1 answer:

lions [1.4K]4 years ago

4 0

X = 7/3
Because 16^1.66667 = 101.593 and 4^3.33333 = 101.593

You might be interested in

In the diagram below, O is circumscribed about quadrilateral ABCD. What is the value of x?

pickupchik [31]

Answer:

50°

Step-by-step explanation:

In an inscribed quadrilateral, the opposite angles are supplementary (angle sum = 180).

2x + 80 = 180

2x = 100

x = 50

3 0

3 years ago

Read 2 more answers

Twenty-one boys and eight girls go on a camping trip. In how many ways can a group of six be selected to gather firewood, given

lorasvet [3.4K]

(a) there are 8C2 = 28 ways of picking 2 girls from 8
And there are 21C4 = 5985 ways of picking 4 boys

Required number of ways for 2g / 4b = 28 * 5985 = 167,580

(b) at least 2 girls means combinations of 2g/4b , 3g,3b , 4g/2b , 5g 1b or
6 girls.

2g/4b = 167,580 ways
3g/3b = 8C3 * 21C3 = 56 * 1330 = 74,480
4g/2b = 8C4* 21C2 = 70 * 210 = 14,700
5g 1b = 8C5* 21 = 56*21 = 1176
6 girls = 8C6 = 28

adding these up we get the answer to (b) which is 257,964

6 0

3 years ago

Geometry help ASAP branliest

Crazy boy [7]

It’s C / what other ratios could you use?

6 0

4 years ago

Given f(x) and g(x) = f(x) + k, look at the graph below and determine the value of k. (1 point)

kati45 [8]

Answer: 4

Step-by-step explanation:

5 0

3 years ago

Growth Models 19515. In 1968, the U.S. minimum wage was $1.60 per hour. In 1976, the minimum wagewas $2.30 per hour. Assume the

VikaD [51]

In general, the exponential growth function is given by the formula below

$f(x)=a(1+r)^x$

Where a and r are constants, and x is the number of time intervals.

In our case, n=0 for 1960; therefore, 1968 is n=8,

$\begin{gathered} f(8)=a(1+r)^8 \\ \text{and} \\ f(8)=1.6 \\ \Rightarrow1.6=a(1+r)^8 \end{gathered}$

And 1976 is n=16

$\begin{gathered} f(16)=a(1+r)^{16} \\ \text{and} \\ f(16)=2.3 \\ \Rightarrow2.3=a(1+r)^{16} \end{gathered}$

Solve the two equations simultaneously, as shown below

$\begin{gathered} \frac{1.6}{(1+r)^8}=a \\ \Rightarrow2.3=\frac{1.6}{(1+r)^8}(1+r)^{16} \\ \Rightarrow2.3=1.6(1+r)^8 \\ \Rightarrow\frac{2.3}{1.6}=(1+r)^8 \\ \Rightarrow(\frac{2.3}{1.6})^{\frac{1}{8}}=(1+r)^{}^{} \\ \Rightarrow r=(\frac{2.3}{1.6})^{\frac{1}{8}}-1 \\ \Rightarrow r=0.0464078 \end{gathered}$

Solving for a,