Answer: infinitely many and none
Step-by-step explanation:
if all variables cancel and you are left with zero, there are infinitely many solutions. if it is false there are no solutions.
Answer: Your answer is going to be 32
Step-by-step explanation:
Step-by-step explanation:
Remember when expanding radicals,
When expanding radicals into two radicals, we don't let our radicand have two negative answers.
We don't do this
OK first convert one of the equations into Y=MX+b form
Y-2x = 3
Add 2X
Y = 2x +3
Now substitute this equation in the other one.
So it would be
3X - 2Y = 5
3X-2(2x+3) = 5
Now solve for y
3X - 4X - 6 = 5
-1X - 6 = 5
Add 6
-1X = 11
X = -11
Now substitute this into one of the equations
Y - 2X = 3
Y -2(-11) = 3
Y +22 = 3
y = 3-22
y = -19
