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goldfiish [28.3K]
3 years ago
15

1/2y+4(y-8)=0 use the zero property

Mathematics
1 answer:
ozzi3 years ago
5 0

Answer:

y=\frac{64}{9}

Step-by-step explanation:

The given expression is \frac{1}{2}y+4(y-8)=0

We  Multiply through by 2 to get:

2*\frac{1}{2}y+2*4(y-8)=0*2

This gives us:

y+8(y-8)=0

Expand the parenthesis using the distributive property

y+8y-64=0

We add 64 to both sides to create a zero pair:

y+8y-64+64=0+64

The zero pair evaluates to zero:

y+8y+0=0+64

By the identity property  of addition, we get

y+8y=64

SImplify:

9y=64

Divide both sides by 9

y=\frac{64}{9}

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A chemical plant has an emergency alarm system. When an emergency situation exists, the alarm sounds with probability 0.95. When
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Answer:

6.56% probability that a real emergency situation exists.

Step-by-step explanation:

We have these following probabilities:

A 0.4% probability that a real emergency situation exists.

A 99.6% probability that a real emergency situation does not exist.

If an emergency situation exists, a 95% probability that the alarm sounds.

If an emergency situation does not exist, a 2% probability that the alarm sounds.

The problem can be formulated as the following question:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem:

What is the probability of a real emergency situation existing, given that the alarm has sounded.

P(B) is the probability of there being a real emergency situation. So P(B) = 0.004.

P(A/B) is the probability of the alarm sounding when there is a real emergency situation. So P(A/B) = 0.95.

P(A) is the probability of the alarm sounding. This is 95% of 0.4%(real emergency situation) and 2% of 99.6%(no real emergency situation). So

P(A) = 0.95*0.04 + 0.02*0.996 = 0.05792

Given that the alarm has just sounded, what is the probability that a real emergency situation exists?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.004*0.95}{0.05792} = 0.0656

6.56% probability that a real emergency situation exists.

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Set the compass slightly larger than half of FG.

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Put the point on G and draw a half circle that intersects FG and faces F.

Draw a line through the intersections of the two half circles, and the intersection of that line with FG is FG's midpoint.

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Step-by-step explanation:

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