Answer:
The 90% confidence interval for the mean time that the drug will take to reduce all fevers for all people is between 304 minutes and 336 minutes
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 40 - 1 = 39
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 39 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 1.685
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 320 - 16 = 304 minutes
The upper end of the interval is the sample mean added to M. So it is 320 + 16 = 336 minutes
The 90% confidence interval for the mean time that the drug will take to reduce all fevers for all people is between 304 minutes and 336 minutes
Answer:
They paid $4.00 per ticket
Step-by-step explanation:
<u>Step 1: Convert words into an inequality</u>
A family buys 6 tickets to a show. They also pay $3 parking fee. They spend $27 to see the show.
6t + 3 = 27
<u>Step 2: Solve for t/tickets</u>
6t + 3 = 27
6t + 3 - 3 = 27 - 3
6t / 6 = 24 / 6
t = 4
Answer: They paid $4.00 per ticket
Subtract 7 from 4 and Mark it on the grid, then, in order to reflect it, mark the same line in the (-,+) corner. (new coordinates are (-5,7)(-5,3)
<span>CD's must be 40 or below, so CD's total≤ 40
If you already have 27, than 27+(number of CDs bought)</span><span>≤ 40
27+x=40(max)
x=(40-27)
x=13 CDs can be bought, at maximum
so (CDs purchased)</span><span> ≤ 13
Therefore, 15 CDs would be too many to fit in the rack </span>
2/3 works here because its value is greater than 1/2 but less than 4/5. An easy way to visualize this is to take the decimal value of each number as decimals are often easier to understand than fractions.
1/2=.50
2/3=.67
4/5=.80
This inequality could be rewritten as .50 < .67 < .80 and would have the same value.
