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3 years ago

Find the sum of the linear expressions (8x - 16) + (-12x - 2)

Mathematics

2 answers:

andreev551 [17]3 years ago

5 0

Answer: -4x-18

Step-by-step explanation:

8x-16-12x-2=8x+-16+-12x+-2

Then you combine like terms.

8x+-16+-12x+-2= (8x+-12x)+(-6+-2)

Your answer will be -4x-18

I hope this helps

Allushta [10]3 years ago

4 0

Answer:

-4x-18

Step-by-step explanation:

pickle

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A metallurgist wants to make 130 grams of an alloy that is to be 20% copper. She has samples that are 14% copper and 22% copper.

bija089 [108]

Answer:

She should use 32.5 g of the sample that contains 14%

Step-by-step explanation:

Here, we want to know the number of grams of the sample that contains 14% copper that should be used

let the number of grams that contains 14% copper to be used be x

Then the number of grams of 22% will be 130-x

Thus, mathematically;

0.14(x) + 0.22(130-x) = 0.2(130)

0.14x + 28.6 - 0.22x = 26

0.22x - 0.14x = 28.6 - 26

0.08x = 2.6

x = 26/0.08

x = 32.5

8 0

3 years ago

For every 2 miles that i run , Rubio runs 5 miles. If i ran 12 miles last week, How many miles did Rubio run ?

liraira [26]

The answer is 30. 2x6 is 12 so you would do 5x6 which is 30

5 0

3 years ago

Please help me right now

siniylev [52]

Answer:J

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Solve for z -p(d+z)=-2z+59

suter [353]

Distribute
-pd-pz=-2z+59
add 2z both sides
-pd-pz+2z=59
add pd to both sides
-pz+2z=59+pd
2z-pz=59+pd
undistribute z
z(2-p)=59-pd
divide bot sides by 2-p
$z=\frac{59-pd}{2-p}$
$z=\frac{pd-59}{p-2}$

7 0

3 years ago

What is the sum of 20x^2-10x-30

ivann1987 [24]

Answer:

The sum of the roots is 0.5

Step-by-step explanation:

The correct question is

What is the sum of the roots of 20x^2-10x-30

we know that

In a quadratic equation of the form

$ax^{2} +bx+c=0$

The sum of the roots is equal to

$-\frac{b} {a}$

in this problem we have

$20x^{2} -10x-30=0$

$a=20\\b=-10\\c=-30$

substitute

$-\frac{(-10)} {20}=0.5$

Verify

Find the roots of the quadratic equation

The formula to solve a quadratic equation is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

$a=20\\b=-10\\c=-30$

substitute

$x=\frac{-(-10)\pm\sqrt{-10^{2}-4(20)(-30)}} {2(20)}$

$x=\frac{10\pm\sqrt{2,500}} {40}$

$x=\frac{10\pm50} {40}$

$x=\frac{10+50} {40}=1.5$

$x=\frac{10-50} {40}=-1$

The roots are x=-1 and x=1.5

The sum of the roots are

$-1+1.5=0.5$ ----> is ok

5 0

3 years ago