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3 years ago

8

The product of -16 and an unknown number equals -256. What is the value of the unknown number?

1 answer:

nikitadnepr [17]3 years ago

6 0

16 is the unknown value.

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Help help ASAP! Can someone help me with the answer!

Monica [59]

Answer:

-2x - 8

Step-by-step explanation:

Combine like terms

-5x - 7x = -2

Therfore you have

-2x - 8

5 0

3 years ago

1(3/11-7d/17) using distributive property

nadezda [96]

D=51/77
First set up the equation equal to zero(0), the distribute from there.

6 0

3 years ago

You buy Apple stock for $120 per share over a period of time the stock value increased at a weekly rate of 5% you sell the stock

Rainbow [258]

Answer:

8.31 weeks

Step-by-step explanation:

Given that the cost of one share of Apple stock, C=$120

Rate is the increment of the stock value, R= 5%/week=0.05 / week.

Assuming that after t week, the stock has been sold for $180.

Since the stock value increased at 5% every week, so, the interest is compounded weekly, so

$S=C\left(1+R\right)^t \\\\ \Rightarrow 180 = 120\left(1+0.05\right)^t \\\\ \Rightarrow 180 = 120\left(1.05 )^t \\\\$

$\Rightarrow \frac{180}{120}=1.05^t \\\\\Rightarrow 1.5=1.05^t$

$\Rightarrow \ln(1.5)=t \ln(1.05)$ [taking log both sides]

$\Rightarrow t=\frac {\ln(1.5)}{\ln(1.05)}=8.31$ weeks

Hence, after 8.31 weeks the stock has been sold for $180.

6 0

3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

What do you think the value of represents in the function? How can you predict what the graph of a quadrati function will look l

allochka39001 [22]

Answer:

Step-by-step explanation:

Parts of the question are missing.

y = a(x-h)² + k is a vertical parabola.

If a is positive, the parabola opens upwards.

If a is negative, the parabola opens downwards.

The vertex is at (h, k)

7 0

2 years ago