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9966 [12]
3 years ago
13

Find the gcf of 40 and 48

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
7 0
I think it might be 4
AysviL [449]3 years ago
3 0

the greatest common factor of 40 and 48 is 8.

the factors of 40 are: 1, 2, 4, 5, / 8 /, 10, 20, 40

the factors of 48 are: 1, 2, 3, 4, 6, / 8 /, 12, 16, 24, 48

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3 years ago
Three friends each have some ribbon. Carol has 90 inches of ribbon, Tino has 7.5 feet of ribbon, and Baxter has 3.5 yards of rib
erastovalidia [21]

Answer: 306 inches or 25.5 feet or 8.5 yards.

Step-by-step explanation:

Given: Carol has 90 inches of ribbon, Tino has 7.5 feet of ribbon, and Baxter has 3.5 yards of ribbon.

1 feet = 12 inches

length of ribbon Tino has = 12 x 7.5 = 90 inches

1 yard = 36 inches

length of ribbon Baxter has = 3.5 x 36 = 126 inches

Total ribbon they have = (length of ribbon Carol has) + (length of ribbon Tino has) + (length of ribbon Baxter has)

= (90+90+126) inches

= 306 inches

In feet , Total ribbon = \dfrac{306}{12}\text{ feet}   [\text{ 1 inch}=\dfrac{1}{12}\text{ feet}]

=\text{25.5 feet}

In yards, Total ribbon =\dfrac{25.5}{3}\text{ yards}    [\text{1 feet}=\dfrac{1}{3}\text{ yard}]

=\text{ 8.5 yards}

Hence, the total length of ribbon the three friends have is 306 inches or 25.5 feet or 8.5 yards.

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3 years ago
Solve for L: P = 2L + 2W
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P = 2L + 2W\\2L=P-2W\\L=\dfrac{P-2W}{2}

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