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ololo11 [35]
3 years ago
10

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma

ils containing the same virus, after which the virus disables itself on that machine.(1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds.(2) Solve the recurrence relation.(3) How many e-mails are sent at the end of 20 seconds

Mathematics
2 answers:
pickupchik [31]3 years ago
8 0

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

hoa [83]3 years ago
6 0

Answer:

The answer is attached below

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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gavmur [86]

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there are 300 student and teachers at a sports event.Grade k to 2 is students: 137 Grade 3 to 5 students: 145 Teachers: ? what i
AVprozaik [17]

Answer:

6%

Percentage of teachers = 6%

Step-by-step explanation:

Given;

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The second angle of a triangle is double the first angle. The third angle is 40 less than the first angle. Find the three angles
ArbitrLikvidat [17]

Answer:

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Step-by-step explanation:

Angle 1: x

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The total degrees for all the angles in a triangle add up to 180, so we now have the equation x+2x+x-40=180. From here we solve to get 55 degrees for x, so angle 1 is 40 degrees, angle 2 is 110 (2 times 40) and the third angle is 15 (55-40).  

6 0
4 years ago
A jacket that is regularly sold for $49.95 is on sale for 25% off. What is the sale price of the jacket?
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First, find 25% of 49.95. Turn 25% into a decimal by dividing by 100.

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49.95 - 12.46 = 37.49

<h2>Answer:</h2>

<u>The discounted price of the jacket is </u><u>$37.49</u><u>.</u>

Now find 8% of 37.49.

8% ⇒ 0.08

Multiply 0.08 by 37.49.

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<u>The tax is </u><u>$2.99</u><u>.</u>

To find the full price, add 37.49 and 2.99 together.

37.49 + 2.99 = 40.48

<h2>Answer:</h2>

<u>The final cost is </u><u>$40.48</u><u>.</u>

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