-9 (5m+2) = 0
-45m - 18 = 0
+18 +18
-45m = 18
-45m/-45 = 18/-45
m= 0.4
The volume of a cone is one-third of the product of the area of the base times the height, i.e.
(1/3)π(r^2)*h = (1/3)π(3cm)^2 *(8cm) = 75.40 cm^3
Now multiply that by the number of cones: 6 * 75.40 cm^3 = 452.40 cm^3.
Then the answer is 452 cm^3
A = P + I
2a = a + PTR/100
2a = a + 5aT/100
2a = a(1+T/20)
2=1+T/20
T=20 yrs
<h3>
Answer: Choice D</h3>
Explanation:
Any time Alyssa is increasing her speed, the graph will move uphill when going from left to right.
If she slows down, then the graph will move downhill when going left to right.
Always move from left to right when reading a graph because this is how the time axis is set up.
Any flat part represents portions where her speed is constant, i.e. doesn't change.
With all that in mind, the answer is choice D because
- The first portion is going uphill (she's increasing her speed). This portion spans horizontally from 0 seconds to 20 seconds.
- The next portion is her slowing down (the graph is going downhill). This portion spans horizontally from 20 seconds to 30 seconds (so we have a 10 second duration).
- The third portion is where Alyssa is driving at some fixed speed that doesn't change. This portion is 20 seconds long.
- The last portion is Alyssa slowing down and coming to a complete stop. This portion is 5 seconds long.
Answer:
a.) f(x) = 
where 90 < x < 120
b.) 
c.)
d.) 
Step-by-step explanation:
Let
X be a uniform random variable that denotes the actual charging time of battery.
Given that, the actual recharging time required is uniformly distributed between 90 and 120 minutes.
⇒X ≈ ∪ ( 90, 120 )
a.)
Probability density function , f (x) = 
where 90 < x < 120
b.)
P(x < 110) = 
= ![\frac{1}{30}[x]\limits^{110}_{90} = \frac{1}{30} [ 110 - 90 ] = \frac{1}{30} [ 20] = \frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B30%7D%5Bx%5D%5Climits%5E%7B110%7D_%7B90%7D%20%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%20110%20-%2090%20%5D%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%2020%5D%20%3D%20%5Cfrac%7B2%7D%7B3%7D)
c.)
P(x > 100 ) = 
= ![\frac{1}{30}[x]\limits^{120}_{100} = \frac{1}{30} [ 120 - 100 ] = \frac{1}{30} [ 20] = \frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B30%7D%5Bx%5D%5Climits%5E%7B120%7D_%7B100%7D%20%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%20120%20-%20100%20%5D%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%2020%5D%20%3D%20%5Cfrac%7B2%7D%7B3%7D)
d.)
P(95 < x< 110) = 
= ![\frac{1}{30}[x]\limits^{110}_{95} = \frac{1}{30} [ 110 - 95 ] = \frac{1}{30} [ 15] = \frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B30%7D%5Bx%5D%5Climits%5E%7B110%7D_%7B95%7D%20%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%20110%20-%2095%20%5D%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%2015%5D%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
