There should be 8 grapes left in the bowl
Answer:
z = 1/9 and z = 1
Step-by-step explanation:
![-9 z^{2} + 10z - 1 = 0](https://tex.z-dn.net/?f=-9%20z%5E%7B2%7D%20%2B%2010z%20-%201%20%3D%200)
![(-9z+1)(z-1) = 0](https://tex.z-dn.net/?f=%28-9z%2B1%29%28z-1%29%20%3D%200)
You can check the answer using foil method
Then,
![(-9z+1) = 0](https://tex.z-dn.net/?f=%28-9z%2B1%29%20%3D%200)
![-9z = -1](https://tex.z-dn.net/?f=-9z%20%3D%20-1)
![z = 1/9](https://tex.z-dn.net/?f=z%20%3D%201%2F9)
![(z-1) = 0](https://tex.z-dn.net/?f=%28z-1%29%20%3D%200)
![z = 1](https://tex.z-dn.net/?f=z%20%3D%201)
Answers:
![z = 1/9](https://tex.z-dn.net/?f=z%20%3D%201%2F9)
![z = 1](https://tex.z-dn.net/?f=z%20%3D%201)
<span>No. Its x=4. You couldn't cut the box to much lower without it being absurd.
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</span>
Answer:
![\sqrt{149\\ \\](https://tex.z-dn.net/?f=%5Csqrt%7B149%5C%5C%20%5C%5C)
However, that's the length of "c" and you're looking to drag it in. So,o you drag in 10^2+7^2=a^2.
Then, as shown by the first picture attatched, you can drag in the one with "c" and "a" with the five shown.
Step-by-step explanation:
To find "c" the diagonal, as explained, you need to use the theorem twice. You can first use it by finding "a", as you already have "b". To find a, you do 10^2+7^2=a^2, the hypotenuse.
100+49=149.
So, a is root 149.
a^2+b^2=c^2 so
149+25=174
Answer:
C
Step-by-step explanation:
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