14r+20<14r+16 or 8−10r>15−9r
14r+20<14r+16
14r+20−14r<14r+16−14r(Subtract 14r from both sides)
20<16
20−20<16−20(Subtract 20 from both sides)
0<−4
8−10r>15−9r
−10r+8>−9r+15(Simplify both sides of the inequality)
−10r+8+9r>−9r+15+9r(Add 9r to both sides)
−r+8>15
−r+8−8>15−8(Subtract 8 from both sides)
−r>7
−r/−1 > 7/−1(Divide both sides by -1)
r<−7
Ur answer is:
r < - 7 OR 0 < - 4
The correct response is X=25
Answer:
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
Step-by-step explanation:
From the given triangle JKL;
Hypotenuse KJ = 10.9
Length LJ is the opposite = 8.9cm
The angle LKJ is the angle opposite to side KJ = x
Using the SOH CAH TOA Identity;
sin theta = opp/hyp
sin LKJ = LJ/KJ
Sinx = 8.9/10.9
x = arcsin(8.9/10.9)
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
Answer:
d
Step-by-step explanation:
Because you need to substitute the variable first, multiply that and add 8.
Answer:
1/6
Step-by-step explanation:
There are 6 possible numbers for the spinner to land on, and only 1 of those cases will be where the spinner lands on 6.
Therefore, the answer is 1/6
