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DiKsa [7]
2 years ago
12

At 8:30 A.M.., Briana started filling a 2,800-gallon pond. At 10:30 A.M., she had filled 1,400 gallons. At what time will the po

nd be full?
Mathematics
1 answer:
Sati [7]2 years ago
3 0

Answer:

12:30 pm

Step-by-step explanation:

8:30 am pond is empty

10:30 am pound is 1,400 gallons full

  time?    pound is 2,800 gallons full

from 8:30 to 10:30 are 2 hours so the rate of filling up is

             1,400 gallons in 2 hours

to have a whole pond filled we need another 2 hours because

in another 2 hours will have another 1,400 gallons so a pound full. 8:30 am + 2hours = 12:30 pm

8:30 am pond is empty

10:30 am pound is 1,400 gallons full

12:30 pm pound is 2,800 gallons full.

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mario62 [17]

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8 0
3 years ago
Hamid bought 4.5 pounds of strawberries. The total cost of the strawberries was $8.10. How much did each pound of strawberries c
ankoles [38]

Answer:

$1.80 per pound

Step-by-step explanation:

divide the cost by the number of pounds of strawberries to get your answer

3 0
3 years ago
Read 2 more answers
use green's theorem to evaluate the line integral along the given positively oriented curve. c 9y3 dx − 9x3 dy, c is the circle
Rina8888 [55]

The line integral along the given positively oriented curve is -216π. Using green's theorem, the required value is calculated.

<h3>What is green's theorem?</h3>

The theorem states that,

\int_CPdx+Qdy = \int\int_D(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y})dx dy

Where C is the curve.

<h3>Calculation:</h3>

The given line integral is

\int_C9y^3dx-9x^3dy

Where curve C is a circle x² + y² = 4;

Applying green's theorem,

P = 9y³; Q = -9x³

Then,

\frac{\partial P}{\partial y} = \frac{\partial 9y^3}{\partial y} = 27y^2

\frac{\partial Q}{\partial x} = \frac{\partial -9x^3}{\partial x} = 27x^2

\int_C9y^3dx-9x^3dy = \int\int_D(-27x^2 - 27y^2)dx dy

⇒ -27\int\int_D(x^2 + y^2)dx dy

Since it is given that the curve is a circle i.e., x² + y² = 2², then changing the limits as

0 ≤ r ≤ 2; and 0 ≤ θ ≤ 2π

Then the integral becomes

-27\int\limits^{2\pi}_0\int\limits^2_0r^2. r dr d\theta

⇒ -27\int\limits^{2\pi}_0\int\limits^2_0 r^3dr d\theta

⇒ -27\int\limits^{2\pi}_0 (r^4/4)|_0^2 d\theta

⇒ -27\int\limits^{2\pi}_0 (16/4) d\theta

⇒ -108\int\limits^{2\pi}_0 d\theta

⇒ -108[2\pi - 0]

⇒ -216π

Therefore, the required value is -216π.

Learn more about green's theorem here:

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3 0
2 years ago
After a rotation of 90° about the origin, the coordinates of the vertices of the image of a triangle are A'(6,3), B'(-2, 1)
Fed [463]

Answer:

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Step-by-step explanation:

Rotation by -90° about the origin is the transformation ...

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So, your pre-image points are ...

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8 0
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Confidence intervals for the means provide an estimate for where the true mean lies.
stepladder [879]

It is true that the confidence intervals for the mean provide an estimate for where the true mean lies.

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The mean is a basic mathematical average of two or more values. There are two sorts of means that may be calculated: the arithmetic mean and the geometric mean. A mean tells you the average of a bunch of values, which helps you contextualize each data point.

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