The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
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Download Photomath it will answer it with step by step work
First step is to simplify the equation so that it makes our life easier! Since 2^2 is equivalent to 4, we can plug that into the equation. Then we can also simplify 2^4 to 16. Now it should look like this:
(4)(2)/16
Now we can solve. 4(2) = 8 so now we have 8/16. 8/16 simplifies to 1/8 when you divide the numerator and the denominator by 8. So there you go! Your final answer is 1/8! I really hope that helped you out, and happy holidays!
Answer:
C
Step-by-step explanation:
For the first one, there is a ratio of change greater than one so that is exponential growth.
The second one has exponential decay but its x is negative making it actually exponential decay even if graphed.
The third one has positive growth over an interval of negative x, so in terms of x there is exponential decay.
The fourth one is neither and if graphed is just points as there is a specific solution set.
In conclusion, the third is exponential decay!
Hope this helps :)
Answer:
there is no table, just a list of numbers. we need a table or maybe a ss for reference
