Answer:
We have function,
Standard Form of Sinusoid is
Which corresponds to
where a is the amplitude
2pi/b is the period
c is phase shift
d is vertical shift or midline.
In the equation equation, we must factor out 2 so we get
Also remeber a and b is always positive
So now let answer the questions.
a. The period is
So the period is pi radians.
b. Amplitude is
Amplitude is 6.
c. Domain of a sinusoid is all reals. Here that stays the same. Range of a sinusoid is [-a+c, a-c]. Put the least number first, and the greatest next.
So using that<em> rule, our range is [6+3, -6+3]= [9,-3] So our range</em> is [-3,9].
D. Plug in 0 for x.
So the y intercept is (0,-3)
E. To find phase shift, set x-c=0 to solve for phase shift.
Negative means to the left, so the phase shift is pi/4 units to the left.
f. Period is PI, so use interval [0,2pi].
Look at the graph above,
Answer:
x = −6
Explanation:
5x + 7y = -23
Y = -2x - 11
Substitute -2x - 11 for y in 5x + 7y = -23
5x + 7(−2x − 11) = −23
Simplify both sides of the equation
5x + 7(−2x − 11) = −23
5x + (7)(−2x ) + (7)(−11) = −23 (Distribute)
5x + −14x + −77 = −23
(5x + −14x) + (−77) = −23 (Combine Like Terms)
−9x + −77 = −23
−9x − 77 = −23
Add 77 to both sides
−9x − 77 + 77 = −23 + 77
−9x = 54
Divide both sides by -9
−9x / -9 = 54 / -9
x = -6
Answer:
324
Step-by-step explanation:
Becasue the data may be skewed right or left (not symmetrical)
that is obvious when the median lean to left or right while the maximum and minimum records are still as they are.
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