BD = 53, AC = 45 & DA = 87. Find BC

Henry has a bag containing 39 letter tiles, some consonants, and some vowels. He selects a tile without looking and then replace

adoni [48]

Answer:

21 consonant tiles

Step-by-step explanation:

Henry has a bag containing 39 letter tiles, some consonants, and some vowels.

He selects a tile without looking and then replaces it. If he pulls 7 consonant tiles and 6 vowel tiles, which is the most likely number of consonant tiles in Henry's bag?

Step 1

We add up the number of tiles that he pulls out of the bag

= 7 consonant tiles + 6 vowel tiles

= 13 tiles

Step 2

We divide the total number of tiles in the bag by the total number of tiles that was pulled out of the bag

= 39 tiles ÷ 13 tiles

= 3

Step 3

The most likely number of consonant tiles in Henry's bag is calculated as:

3 × The number of consonant tiles that was pulled out of the bag.

Hence:

3 × 7 consonant tiles

= 21 consonant tiles.

Therefore, the most likely number of consonant tiles in Henry's bag is 21 consonant tiles.

4 0

2 years ago

The time for a professor to grade an exam is normally distributed with a mean of 16.3 minutes and a standard deviation of 4.2 mi

dem82 [27]

Answer:

62.17% probability that a randomly selected exam will require more than 15 minutes to grade

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 16.3, \sigma = 4.2$