Do you have a picture we can see?
X - 3(x + 4)
-------------
x^2 - 1
vertical asymptoes happen when the denominator = 0
x^2 - 1 = 0
so x = 1 or -1
so the asymptotes are x = -1 and x=1
Answer:
(6,3)
Step-by-step explanation:
y=2/3 x - 1
y=-1/2 x + 6
Since both equations are equal to y, we can set them equal
2/3 x - 1 =-1/2 x + 6
We have fractions, so I will multiply by 6 to clear the fractions
6(2/3 x - 1) =(-1/2 x + 6)6
Distribute
4x -6 = -3x +36
Add 3x to each side
4x+3x -6 = -3x+3x +36
7x -6 = 36
Add 6 to each side
7x-6+6 = 36+6
7x = 42
Divide each side by 7
7x/7 = 42/7
x =6
Now we need to find y
y =2/3x -1
y = 2/3(6) -1
y = 4-1
y=3
(6,3)
Hey there.
4(2.1k - 4) = 6(3.4k - 2); apply the distributive property to remove the parenthesis.
8.4k - 16 = 20.4k - 12; Get the variable to one side, so subtract 8.4k.
-16 = 12k - 12; isolate the variable by adding 12.
-4 = 12k; divide by 12 to solve for our variable.
k = -1/3
I hope this helps!
2(3a+8) I used photo math, and it gave me a step by step. The top steps are factor the expressions (20a+4)-(14a-12), which is (4(5a+1)-2(7a-6)
