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Korolek [52]
4 years ago
11

Let w = x2 + y2 + z2, x = uv, y = u cos(v), z = u sin(v). use the chain rule to find ∂w ∂u when (u, v) = (9, 0).

Mathematics
1 answer:
jasenka [17]4 years ago
7 0
By the chain rule,

\dfrac{\partial w}{\partial u}=\dfrac{\partial w}{\partial x}\cdot\dfrac{\partial x}{\partial u}+\dfrac{\partial w}{\partial y}\cdot\dfrac{\partial y}{\partial u}+\dfrac{\partial w}{\partial z}\cdot\dfrac{\partial z}{\partial u}
\dfrac{\partial w}{\partial u}=2xv+2y\cos v+2z\sin v

We also have x(9,0)=0, y(9,0)=9, and z(9,0)=0, so at this point we get

\dfrac{\partial w}{\partial u}(9,0)=2\cdot9\cdot\cos0=18
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Treena flew home to visit her family for
devlian [24]

x + y = 71.5

x = 47.8

y = 71.5 - 47.8

71.5 - 47.8 = 23.7

y = 23.7 pounds

7 0
2 years ago
11. Given: TQ bisects ZRTP, QS || PT<br> RT = 30. Find QP, RS and QS
yaroslaw [1]

QP=24 cm

RS=11.25 cm

QS=18.75 cm

<u>Explanation</u>:

Given that TQ bisects <RTP

therefore(1)

consider ΔRQS and ΔRPT

QS||PT,RP and RT are transversals

(alternate angles)(2)

comparing (1) and (2)

and triangle SQT is isocelus

Therefore SQ=ST(sides opposite to equal angles in an isocelus triangle)

Therefore <RQS=<RPT(corresponding angles)

<RSQ=<RTP(corresponding angles)

therefore by AA criterion for similarity

ΔRQS~ΔRPT

According to the property of similar triangles

RQ/RP=RS/RT=QS/PT9/RP=X/30=QS/50\\9/RP=X/30=(30-X)/50\\X/30=(30-X)/50\\50X=30(30-X)\\50X=900-30X\\50X+30X=900\\80X=900\\X=900/80=11.25\\RS=11.25 cm\\QS=30-X=30-11.25\\QS=18.75 cm\\9/RP=X/30\\9/RP=11.25/30\\9*30/11.25=RP\\RP=24 cm

3 0
3 years ago
It has been estimated that 72.7% of alcoholics need professional help to stop drinking. What is the probability that a random al
Svetradugi [14.3K]

The probability that a random alcoholic can kick the habit without professional help is 0.273 .

<h3>What is Probability ?</h3>

Probability is the study of likeliness of an event to happen.

It has a range of 0 to 1 , where 0 indicates uncertainty and 1 indicates certainty.

It is given that

The alcoholics that need professional help to stop drinking is 72.7 %

Therefore the probability of this is 72.7 /100 = 0.727

The probability that they will not need professional help is given by

q = 1 - p

q = 1 -0.727

q = 0.273

Therefore the probability that a random alcoholic can kick the habit without professional help is 0.273 .

To know more about Probability

brainly.com/question/11234923

#SPJ1

5 0
2 years ago
The picture has the question.
Alekssandra [29.7K]

Answer: 180 tickets for $40

Step-by-step explanation:

    To answer this question, we need to find a pattern;

15 / 3 = 5

60 / 15 = 4

-> If you divide, we find a pattern of the quotient with 5... 4... so we can assume the next is 3

    Using this pattern;

60 * 3 = 180 tickets for $40

8 0
2 years ago
Is 1.65 greather than 16.5
Bas_tet [7]

Answer:

No

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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