“The breaking distance is directly proportional to the square of its speed”
Using your variables, this means: d = k•b^2
k here is some unknown (and for this question irrelevant) number.
Now if b (the speed) is increased by 200%, then your new speed is b+2b = 3b. The 2b is the 200% increase.
Throw 3b into the first equation we have the new d as:
d = k • (3b)^2
Simplifying this, you have d = k•9b or d=9kb
This means the new braking distance is 9 times the original braking distance.
(3n-10p)^2
=(3n-10p)(3n-10p)
=9n^2-10p-10p+100p^2
=9n^2-20p+100p^2
Answer:
Frequency is 2, 2 and 3.
Step-by-step explanation:
Temp in 101 to 106 - In this range only 2 temperature is there 104 and 104 in 2 cities. so frequency is 2.
Temp in 107 to 112 - In this range only 2 temperature is there 107 and 112 in 2 cities. so frequency is 2.
Temp in 113 to 118 - In this range only 3 temperature is there 114, 117 and 118 so frequency is 3.
Answer:
c
Step-by-step explanation:
right now 15 is the mode because there are 3 of them
if we made it so that there was another 8 there would also be 3 of them
this would mean that there are two modes
