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vovikov84 [41]
3 years ago
14

Each leg of an isosceles triangle is 9 inches

Mathematics
2 answers:
Nastasia [14]3 years ago
8 0
<u><em>B) 41"</em></u>
If the legs of 41" are 9" less than half the base, the base is:
(41-9) 2 = 64
All sides of the triangle added together (perimeter):
41" + 41" + 64" = 146"
Hope this helps! ~<em>ArchimedesEleven</em>
Scilla [17]3 years ago
5 0
Let, the base of the given isosceles triangle be "x"
Now,
If the base is x, then the length of the legs will be 9+ \frac{1}{2}x
Now, 
Perimeter = sum of all sides
146 = (9+ \frac{1}{2}x )+(9+ \frac{1}{2}x)+x

146 = 18+x+x

146 - 18 = 2x

128 = 2x

\frac{128}{2} =x

64 =x

Now, substitute the value of x in the equation for legs of the triangle,

legs = 9+ \frac{1}{2}x
     
       = 9+ \frac{1}{2}(64)
   
       = 9+ 32
 
       = 41 inches.

So, the answer to your question is B.


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