Answer:
R=-12
Step-by-step explanation:
6(1 + 3R) = 2(10R - 9) -4R
Distribute 6 through the parentheses
6+18R=2(10R-9)-4R
Distribute 2 through the parentheses
6+18R=20R-18-4R
Collect like terms
6+18R=16R-18
Move the variable to the left-hand side and change its sign
6+18R-16R=-18
Move the constant to the right-hand side and change its sign
18R-16R=-18-6
Collect like terms
2R=-18-6
Calculate the difference
2R=-24
Divide both sides of the equation by 2
R=-12
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Answers with Explanation.
i. If we raise a number to an exponent of 1, we get the same number.

ii. If we raise 10 to an exponent of 2, it means we multiply 10 by itself two times.

iii. If we raise 10 to an exponent of 3, it means we multiply 10 by itself three times.

iv. If we raise 10 to an exponent of 4, it means we multiply 10 by itself four times.

v. If we raise 10 to an exponent of 5, it means we multiply 10 by itself five times.


vi. Recall that,

We apply this law of exponents to obtain,

vii. We apply

again to obtain,
Answer:
59
Step-by-step explanation:
We know that all the angles must add up to 180
so we have
38+2b-20+b-15=180
solve for b
3b+3=180
3b=177
b=59
Answer: D
<u>Step-by-step explanation:</u>
The first matrix contains the coefficients of the x- and y- values for both equations (top row is the top equation and the bottom row is the bottom equation. The second matrix contains what each equation is equal to.
![\begin{array}{c}2x-y\\x-6y\end{array}\qquad \rightarrow \qquad \left[\begin{array}{cc}2&-1\\1&-6\end{array}\right] \\\\\\\begin{array}{c}-6\\13\end{array}\qquad \rightarrow \qquad \left[\begin{array}{c}-6\\13\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7D2x-y%5C%5Cx-6y%5Cend%7Barray%7D%5Cqquad%20%5Crightarrow%20%5Cqquad%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-1%5C%5C1%26-6%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5C%5Cbegin%7Barray%7D%7Bc%7D-6%5C%5C13%5Cend%7Barray%7D%5Cqquad%20%5Crightarrow%20%5Cqquad%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D-6%5C%5C13%5Cend%7Barray%7D%5Cright%5D)
The product will result in the solution for the x- and y-values of the system.