Answer:
A: The interquartile range is 8.
Step-by-step explanation:
Hopefully this helps!
The answer is 60 because
40-10*2=60
hope it helps
The velocity of the ship = 22 ∠157° = (22 cos 157°) i+ (22 sin 157°) j
The velocity of current = 5 ∠213° = (5 cos 213°) i+ (5 sin 213°) j
So, the resultant velocity = 22 ∠157° + 5 ∠213°
= (22 cos 157°) i+ (22 sin 157°) j + (5 cos 213°) i+ (5 sin 213°) j
= (22 cos 157° + 5 cos 213°) i + (22 sin 157° + 5 sin 213°) j
= -24.444 i + 5.873 j
= 25.14 ∠166.5°
The correct answer is option (1)
<span>1) 25 knots at 166.5 degree</span>
The correct answer is 5/7 or 0.7142857
Hope this helps you! :)
